Question

对C来说很新。当我运行我的讲师给我们开始的代码时，我不断收到此错误。

#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>
#include <time.h>
#include <stdlib.h>

//Create a struct for customers
struct customer
{
char lastName[15];
char firstName[15];
unsigned int customerNumber;
};


struct customer customerRecord;
struct customer *customerPtr;
struct customer other;

customerPtr = &customerRecord;

//typedef struct customer to customer
typedef struct customer customer;

char main()
{
//customerRecord.lastName = Flacco;

}

我收到错误错误C2040：'customerPtr'：'int'的间接级别与'customer *'

不同

我已经阅读了与此相似的其他帖子，但我想我不明白中的答案与他们的计划有关。

谢谢！

Answer 1

此分配错误（在全局范围内不允许分配）：

customerPtr = &customerRecord;

你应该改为：

...
struct customer customerRecord;
struct customer *customerPtr = &customerRecord;  /* definition & initialization */
struct customer other;
...

或

struct customer customerRecord;
struct customer *customerPtr;  /* definition */
struct customer other;

...

int main()
{
  customerPtr = &customerRecord;  /* initialization */

  ...
}

此外，main的返回类型应为int

C错误：C2040：'customerPtr'：'int'与'customer *'的间接级别不同

1 个答案: