Question

这是一个调用方法x次数的while循环。

while (count<=rounds){
    System.out.println("Round " + round);
    PlayerVsPlayer.results();
    count++;
    round++;            
}

PlayerVsPlayer.results（）询问用户输入并调用另一个语句。

        Scanner scan = new Scanner(System.in);
        System.out.print("Choose (R)ock, (P)aper, or (S)cissors:");
        String Player1 = scan.nextLine();
        System.out.print("Choose (R)ock, (P)aper, or (S)cissors:");
        String Player2= scan.nextLine();
        String[] Results = compare.winScore(Player1, Player2);

这是compare.winScore（Player1，Player2）中if else语句的片段：

static String[] winScore(String x, String y){

    if (x.equals(y)) {
        winnerScoreRule.add("Round results is a tie, no one wins.");
        winnerScoreRule.add("");
        winnerScoreRule.add("");
    }
    else if ((x.equals("Rock")) && (y.equals("Paper"))){
        score2++; count++;
        winnerScoreRule.add("Player 2 wins this round!");
        winnerScoreRule.add("The score is " + score1 +" to "+ score2);
        winnerScoreRule.add("Paper beats rock!"); // etc.
    }

我遇到的问题是if else语句第一次执行时，它完美地运行。第二次，if else语句跳过并返回第一次调用的值。有谁知道为什么会这样？谢谢你的帮助！

Answer 1

我重写了这个winScore方法来检查＆＃34;其他＆＃34;例。

static String[] winScore(String x, String y){

        if (x.equals(y)) {
            winnerScoreRule.add("Round results is a tie, no one wins.");
            winnerScoreRule.add("");
            winnerScoreRule.add("");
        }
    //you're asking them to enter (R), (P) or (S)
        else if ((x.toLowerCase().equals("r")) && (y.toLowerCase().equals("p"))){
            score2++; count++;
            winnerScoreRule.add("Player 2 wins this round!");
            winnerScoreRule.add("The score is " + score1 +" to "+ score2);
            winnerScoreRule.add("Paper beats rock!"); // etc.
        }
       ....//other logic for Rock Paper Scissors
        else
       {
           throw WrongOptionSelectedException(); //custom exception for wrong entry
        }

如果else语句在第二次调用时跳过

1 个答案: