Question

我在FormView中有文件上传控件，并且当我尝试更新FormView时，FormView在更新面板内，但是一切正常，但是文件上载后的图像路径不会在GridView1行命令后保存，请帮助我......

page.aspx

<asp:UpdatePanel ID="upnl1" runat="server">
            <ContentTemplate>
                <asp:FormView ID="FormView1" runat="server" DataSourceID="ObjectDataSource1" Width="20px">
                     <InsertItemTemplate>
                        <table>
         <tr>
                                <td style="border-style: dashed dashed dashed none; dashedborder-style: none dashed none dashed;
                                    border-width: thin; border-color: #000000;">
                                    <asp:Label ID="Label14" runat="server" Text="user" BorderStyle="None"></asp:Label>
                                </td>
                                <td style="border-style: dashed none dashed none; border-width: thin; border-color: #000000;">
                                    <uc1:Employee ID="UCEmployee" runat="server" />
                                </td>
                                <td style="border-style: dashed none dashed none; border-width: thin; border-color: #000000;">
                                    <asp:Label ID="Label15" runat="server" Text="percent"></asp:Label>
                                </td>
                                <td style="border-style: dashed none dashed dashed; border-width: thin; border-color: #000000;">
                                    <asp:TextBox ID="txtPartnership" runat="server" Width="60px"></asp:TextBox>
                                    <asp:ImageButton ID="imgAddPersonel" runat="server" ImageUrl="~/App_Themes/images/icons/add.gif"
                                        OnClick="imgAddPersonel_Click" />
                                </td>
                            </tr>
                            <tr>
                                <td style="border-style: none dashed dashed dashed; border-width: thin; border-color: #000000;"
                                    colspan="4">
                                    &nbsp;
                                    <asp:GridView ID="GridView1" runat="server" OnRowCommand="GridView1_RowCommand">
                                    </asp:GridView>
                                </td>
                            </tr>
    <tr>
                                  <td>
                                    <asp:Label ID="Label20" runat="server" Text="attachment" ></asp:Label>                        
                            </td>
                                  <td colspan="3">
                                    <asp:FileUpload ID="FileUpload1" runat="server"/>
                            </td>
                            </tr>
      </table>
                    </InsertItemTemplate>
                    <ItemTemplate>
                        <asp:Image ID="Image1" runat="server" />
                    </ItemTemplate>
                </asp:FormView>

.cs文件

protected void imgAddPersonel_Click(object sender, ImageClickEventArgs e)
    {
           entity.EmployeeId = lovid;
            entity.Partnership = Partnership;
            entity.EmployeeFullName = USEmployee.Des;
            Listentity.Add(entity);
            HttpContext.Current.Session["Listentity"] = Listentity;
            datagridbind(ref gd);
            USEmployee.LOVId = null;
            USEmployee.Des = "";
            txtPartnership.Text = "";
            USEmployee.Focus();
        }
    }
    protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
    {
        if (e.CommandName == "Delete1")
        {
            GridView gd = ((GridView)FormView1.FindControl("GridView1"));
            int rowindex = int.Parse(e.CommandArgument.ToString());
            int employeeid = (int)gd.DataKeys[rowindex]["EmployeeId"];
            Listentity = (List<SuggestionEmployee>)Session["Listentity"];
            Listentity.RemoveAt(rowindex);
            Session["Listentity"] = Listentity;
            datagridbind(ref gd);      
        }
    }

protected void FormView1_DataBound(object sender, EventArgs e)
    {
        if (FormView1.CurrentMode == FormViewMode.Insert)
        {
            ImageButton lb = (ImageButton)FormView1.FindControl("imgAddPersonel");
            ScriptManager.GetCurrent(Page).RegisterPostBackControl(lb);

        }
    }

Answer 1

说明

这是Fileupload控件通常会出现的问题。您的FileUpload控件将没有图像路径，因为您的文件上传控件位于UpdatePanel。当您运行程序时，UpdatePanel将向服务器发送请求，并且该请求将发送到ajax，因此文件上载控件不会被触发，也无法按预期工作。

<强> ANSWER

您需要移除FileUpload控件并将其放在UpdatePanel旁边。然后它将按预期工作。我希望这些信息对您有用。

度过美好的一天。

Fileupload在更新面板内的FormView中无法正常工作

1 个答案: