Question

我有以下JSON响应，需要解析为一个类。由于它没有任何root，我不知道如何解析它。

 [{
    "Id":18,
    "Name":"Albume One",
    "SubTitle":null,
    "Description":null,
    "Date":"3/7/2014 8:00 PM",
    "City":null,
    "State":null,
    "Production":13
    },
    {"Id":200,

我使用以下代码，但不知道如何遍历结果集的每个字段：

        JSONParser parser = new JSONParser();
        JSONArray msg = (JSONArray)parser.parse(buff.readLine());
        for(int i=0;i<msg.size();i++)
        {
            System.err.println(msg.get(0).toString());

        }



 {"Id":18,"Name":"Albume One","SubTitle":null,"Description":null,"Date":"3/7/2014 8:00 PM","City":null,"State":null,"Production":13}
 {"Id":200, .....

是否有任何库可以自动解析JSON而不是使用循环，例如用于XML的Jackson库。

Answer 1

使用以下

JSONParser parser=new JSONParser();

  System.out.println("=======decode=======");

  String s="[0,{\"1\":{\"2\":{\"3\":{\"4\":[5,{\"6\":7}]}}}}]";
  Object obj=parser.parse(s);
  JSONArray array=(JSONArray)obj;
  System.out.println("======the 2nd element of array======");
  System.out.println(array.get(1));
  System.out.println();

  JSONObject obj2=(JSONObject)array.get(1);
  System.out.println("======field \"1\"==========");
  System.out.println(obj2.get("1"));    


  s="{}";
  obj=parser.parse(s);
  System.out.println(obj);

  s="[5,]";
  obj=parser.parse(s);
  System.out.println(obj);

  s="[5,,2]";
  obj=parser.parse(s);
  System.out.println(obj);

Answer 2

你不需要根它。只需将其视为JSON数组并解析它。你将获得一组JSON对象。迭代它并获得你想要的价值......

尝试类似：

JSONParser parser = new JSONParser();
    JSONArray msg = (JSONArray)parser.parse(buff.readLine());
    for(int i=0;i<msg.length();i++)
    {
          JSONObject jsonobj=   msg.getJSONObject(i);
      sysout(jsonobj.get("KEY"));

    }

Answer 3

您可以使用gson api来实现此目的。以下是示例代码：

public class Bean {
        private int Id;
        private String Name;
        private String SubTitle;
        private String Description;
        private String Date;
        private String City;
        private String State;
        private int Production;
        public int getId() {
            return Id;
        }
        public void setId(int id) {
            Id = id;
        }
        public String getName() {
            return Name;
        }
        public void setName(String name) {
            Name = name;
        }
        public String getSubTitle() {
            return SubTitle;
        }
        public void setSubTitle(String subTitle) {
            SubTitle = subTitle;
        }
        public String getDescription() {
            return Description;
        }
        public void setDescription(String description) {
            Description = description;
        }
        public String getDate() {
            return Date;
        }
        public void setDate(String date) {
            Date = date;
        }
        public String getCity() {
            return City;
        }
        public void setCity(String city) {
            City = city;
        }
        public String getState() {
            return State;
        }
        public void setState(String state) {
            State = state;
        }
        public int getProduction() {
            return Production;
        }
        public void setProduction(int production) {
            Production = production;
        }



    }

进行测试：

@Test
    private void test() {

        Gson g = new Gson();
        String jsonString = "[{ \"Id\":18, \"Name\":\"Albume One\", \"SubTitle\":null, \"Description\":null, \"Date\":\"3/7/2014 8:00 PM\", \"City\":null, \"State\":null, \"Production\":13 }]";
        Type token = new TypeToken<List<Bean>>(){}.getType();
        List<Bean> list = g.fromJson(jsonString, token);
        for (Bean bean : list) {
            System.out.println(bean.getName());
        }
    }

Answer 4

取决于您使用的工具包......

JSONArray array = parser.parse(jsonString);
for (JSONObject object : array) {
    int id = object.getInt("Id");
    String name = object.getString("Name");
    ....
}

如何解析没有列表名称的JSON响应

4 个答案: