在C#Form应用程序中使用BackGroundWorker更新UI线程

时间:2014-03-14 12:13:55

标签: c# multithreading user-interface backgroundworker invoke

我有一项耗时的任务,可以测试几个网络连接。在我下面的例子中,我将它限制在一个连接中。 通常,连接会快速返回,但可能会发生无法建立连接以致套接字超时的情况。在这段时间我想在表单中显示一个“闲人”gif,当连接成功时应用程序应该将表单中的图像更改为某些 绿色检查图标或如果连接失败,应显示红色图标“塞子”。

不知怎的,我无法让闲人的GIF变得可见和动画。要模拟失败的连接,可以输入无效的端口#或不存在的地址。

有什么线索我错过了什么或做错了什么?

    partial class Form1
    {
        /// <summary>
        /// Required designer variable.
        /// </summary>
        ///         
     #region BackgroundWorker

        private System.ComponentModel.BackgroundWorker backgroundWorker = new System.ComponentModel.BackgroundWorker();
        private delegate void SomeLongRunningMethodHandler(object sender, EventArgs e);

     #endregion
        private System.ComponentModel.IContainer components = null;

        Button button,button2;
        static Socket socket;
        static bool success;
        private static bool done;
        private Label lbl1;
        private Label lbl2;
        private TextBox address;
        private TextBox port;
        private PictureBox p;
        private static String port_number,host;


        /// <summary>
        /// Clean up any resources being used.
        /// </summary>
        /// <param name="disposing">true if managed resources should be disposed; otherwise, false.</param>
        protected override void Dispose(bool disposing)
        {
            if (disposing && (components != null))
            {
                components.Dispose();
            }
            base.Dispose(disposing);
        }

        private void RunTest(object o,EventArgs e)
        {
            p.Visible = true;
            SomeLongRunningMethodHandler synchronousFunctionHandler =
                default(SomeLongRunningMethodHandler);
            synchronousFunctionHandler = 
                TestConnection;
            synchronousFunctionHandler.Invoke(o, e);
        }

        private void TestConnection(object o, EventArgs e)
        {
            host = address.Text;
            port_number = port.Text;
           if (null != socket)
            {
                socket.Close();
            }

             Thread.Sleep(1000);
             IPEndPoint myEndpoint = new IPEndPoint(0, 0);


            IPHostEntry remoteMachineInfo = Dns.GetHostEntry(host);
            IPEndPoint serverEndpoint = new IPEndPoint(remoteMachineInfo.AddressList[0],
                int.Parse(port_number));



            socket = new Socket(myEndpoint.Address.AddressFamily, SocketType.Stream, ProtocolType.Tcp);
            try
            {
                socket.Connect(serverEndpoint);
                success = true;
                p.Image = global::BlockingUI.Properties.Resources.accept;
            }
            catch
            {
                success = false;
                p.Image = global::BlockingUI.Properties.Resources.stopper;
            }
            done = true;
        }  


        private void ExitApp(object o, EventArgs e)
        {
            Application.Exit();
        }

    }

2 个答案:

答案 0 :(得分:3)

如果你真的想使用BackgroundWorker,这个(或接近它的东西)应该指向正确的方向。您正在创建一个BackgroundWorker对象,但之后无法执行任何操作。不允许BackgroundWorker个对象访问UI元素,因为它们归UI线程所有,但您可以传入UI值,就像我在这里使用Tuple一样(您可以创建自己的类来保存)如果您也想要这些值,然后在工作完成后从UI线程修改UI。

private struct ConnectionProperties
{
    public string Address;
    public string Port;
}

private void RunTest(object o, EventArgs e)
{
    BackgroundWorker worker = new System.ComponentModel.BackgroundWorker();

    worker.RunWorkerCompleted += TestComplete;
    worker.DoWork += TestConnection;

    p.Visible = true;

    //worker.RunWorkerAsync(new Tuple<string, string>(address.Text, port.Text));
    worker.RunWorkerAsync(new ConnectionProperties{ Address = address.Text, Port = port.Text });
}

private void TestConnection(object sender, DoWorkEventArgs e)
{
    bool success = false;
    //var connection = e.Argument as Tuple<string, string>;
    var connection = (ConnectionProperties)e.Argument;

    if (null != socket)
    {
        socket.Close();
    }

    Thread.Sleep(1000);

    IPEndPoint myEndpoint = new IPEndPoint(0, 0);
    IPHostEntry remoteMachineInfo = Dns.GetHostEntry(connection.Address);
    IPEndPoint serverEndpoint = new IPEndPoint(remoteMachineInfo.AddressList[0],
      int.Parse(connection.Port));

    socket = new Socket(myEndpoint.Address.AddressFamily, SocketType.Stream, ProtocolType.Tcp);

    try
    {
        socket.Connect(serverEndpoint);
        success = true;
    }
    catch
    {
        success = false;
    }

    e.Result = success;
}

// Define other methods and classes here
private void TestComplete(object sender, RunWorkerCompletedEventArgs e)
{
    if (e.Error == null)
    {
        var success = (bool)e.Result;
        if (success)
        {
            p.Image = global::BlockingUI.Properties.Resources.accept;
        }
        else
        {
            p.Image = global::BlockingUI.Properties.Resources.stopper;
        }
    }
    else
    {
        //unexpected error, show message or whatever
    }
}

答案 1 :(得分:1)

好吧,我用自己的线程完成了这个。通常,您使用长时间运行的任务运行线程,并在需要时调用Control.Invoke(),其中委托指向将在UI上运行的函数。看起来您正在使用后台工作线程更改UI,这是不允许的。

此外,在Winforms中需要调用Control.Invalidate()来强制重新绘制UI并显示新图标。