UUID疯狂与mssql

时间:2014-03-14 10:50:15

标签: sql-server scala uuid

我的数据库条目有一个带有值的UUID(使用Microsoft SQL Server Management Studio提取)

  

CDF86F27-AFF4-2E47-BABB-2F46B079E98B

将此文件加载到我的Scala应用程序后,toString方法会生成此值

  

276ff8cd-f4af-472e降低-BABB-2f46b079e98b

这是怎么发生的?当我手边只有 CDF86F27-AFF4-2E47-BABB-2F46B079E98B 的字符串时,如何以编程方式创建UUID实例?

相关的光滑代码(前者:表定义,后者:数据库访问对象)

class ChannelTable(tag: Tag) extends Table[ChannelTuple](tag, "Channel") {
  def id = column[UUID]("Id", O.PrimaryKey)
  def channelId = column[Int]("Channel_Id", O.NotNull)
  def timer = column[UUID]("Timer_Id", O.NotNull)
  def from = column[Timestamp]("FromTime", O.NotNull)
  def to = column[Timestamp]("ToTime", O.NotNull)
  def mon = column[Boolean]("Mon", O.NotNull)
  def tues = column[Boolean]("Tues", O.NotNull)
  def wed = column[Boolean]("Wed", O.NotNull)
  def thu = column[Boolean]("Thu", O.NotNull)
  def fri = column[Boolean]("Fri", O.NotNull)
  def sat = column[Boolean]("Sat", O.NotNull)
  def sun = column[Boolean]("Sun", O.NotNull)
  def * = (id, channelId, timer, from, to, mon, tues, wed, thu, fri, sat, sun)
}

object ChannelDAO extends EntityDAO[Channel, ChannelTuple] {
  private val entities = TableQuery[ChannelTable]
  [...]
  override def get(id: UUID)(implicit session: Session): Option[Channel] = {
    val y = for {
      a <- entities if a.id === id
    } yield (a)
    if (y.list.length > 1) throw new NonUniqueResultException
    y.firstOption
  }
  [...]
}

2 个答案:

答案 0 :(得分:1)

Slick将UUID转换为uniqueidentifier,与SQL Server不同。

在.NET / SQL Server中未指定endianness。

如果从MSSQL获取UUID,请确保对UUID使用大端编码与JVM保持一致。

查看此SO帖子。看起来您需要创建一个翻译UUID的方法。

How to read a .NET Guid into a Java UUID

答案 1 :(得分:0)

对我来说很好:

> val uuidString = "CDF86F27-AFF4-2E47-BABB-2F46B079E98B"
uuidString: String = CDF86F27-AFF4-2E47-BABB-2F46B079E98B

> java.util.UUID.fromString(uuidString)
res2: java.util.UUID = cdf86f27-aff4-2e47-babb-2f46b079e98b