Question

我试图检查一个字符串是否等于另一个字符串，除了sting内括号内的不同数字变量。任何人都可以帮助我吗？

#example name: "hername: [485]"

name = "myname"
random_name = #random string from a list
objectname = (str(random_name))+": [#any number]")

if objectname.startswith(str(name)):
    #do something

Answer 1

最严格的测试是使用正则表达式：

import re

if re.search(r'^{}: \[\d+\]$'.format(re.escape(name)), objectname):

这将匹配完全等于name: [number]的字符串，其中number由1位或更多位数组成。

如果您的对象名称始终遵循该模式，您可以不那么严谨并只测试name: [，并且您可以假设在括号后面总是有一个数字：

if objectname.startswith('{}: ['.format(name)):

或者更简单，假设你的所有名字总是以: [number]结尾，只测试冒号前的名字：

if objectname.partition(':')[0] == name:

演示：

>>> import re
>>> objectnames = 'hername: [485]', 'myname: [42]', 'myname: [81]'
>>> name = 'myname'
>>> for objectname in objectnames:
...     if re.search(r'^{}: \[\d+\]$'.format(re.escape(name)), objectname):
...         print objectname, 'matches'
... 
myname: [42] matches
myname: [81] matches
>>> for objectname in objectnames:
...     if objectname.startswith('{}: ['.format(name)):
...         print objectname, 'matches'
... 
myname: [42] matches
myname: [81] matches
>>> for objectname in objectnames:
...     if objectname.partition(':')[0] == name:
...         print objectname, 'matches'
... 
myname: [42] matches
myname: [81] matches

Answer 2

你必须创建正则表达式。

import re

name = "myname"
random_name = #random string from a list
objectname = (str(random_name))+": [#any number]")
prog = re.compile(name+':.\[\d+\]')
if prog.match(objectname):
    #do something

检查字符串但跳过括号内的数字？

2 个答案: