Question

我在下面有一些源代码可以重现这一点。在HUD有机会出现之前调用showWithStatus并解除，导致控件在下次调用showWithStatus时不显示。有没有人知道任何变通办法？

// Commenting these will show SVProgressHUD
[SVProgressHUD showWithStatus:@"Loading..."];
[SVProgressHUD dismiss];
// Comment above to show SVProgressHUD

[SVProgressHUD showWithStatus:@"Loading..."];
[self performSelector:@selector(dismissHUD) withObject:nil afterDelay:5.0f];

编辑：我在这里有一些source code可以重现这一点。

Answer 1

我为第二次HUD显示做了这个：

[self performSelector:@selector(showHud) withObject:nil afterDelay:0.1];

Answer 2

我已经解决了这个问题：

<强> 1。添加属性

@property (nonatomic, readonly, getter = isDismissing) BOOL dismissing;

2.add flag

- (void)dismissWithDuration:(NSTimeInterval)duration delay:(NSTimeInterval)delay {
    _dismissing = YES;
    ...
        void (^completionBlock)(void) = ^{
            ...
            _dismissing = NO;
        };
    ...
}

重命名功能

- (void)showImage:(UIImage)image status:(NSString)status duration:(NSTimeInterval)duration

以姓名

- (void)showImageSS:(UIImage)image status:(NSString)status duration:(NSTimeInterval)duration

3.延迟

- (void)showImage:(UIImage*)image status:(NSString*)status duration:(NSTimeInterval)duration
{
    if(self.isDismissing){
        __weak SVProgressHUD *weakSelf = self;
        dispatch_after(dispatch_time(DISPATCH_TIME_NOW, NSEC_PER_SEC * SVProgressHUDDefaultAnimationDuration),dispatch_get_main_queue(), ^{
            [weakSelf showImageSS:image status:status duration:duration];
        });
    }else{
        [self showImageSS:image status:status duration:duration];
    }
}

- (void)showImageSS:(UIImage*)image status:(NSString*)status duration:(NSTimeInterval)duration
{
    // this is orginal function - (void)showImage:(UIImage)image status:(NSString)status duration:(NSTimeInterval)duration code block
}

finsh谢谢大家

SVProgressHUD - 显示/隐藏控件快速导致它在下次调用showWithStatus时不会出现

2 个答案: