Question

我有linux utils代码（可以在这里找到：https://www.kernel.org/pub/linux/utils/util-linux/）而且我只需要libuuid，没有别的。我已经尝试设置了许多'--disable-'标志，但它似乎仍在编译我不需要的东西。

这是我的实际配置命令：

./configure --disable-libblkid --disable-libmount --disable-mount --disable-losetup --disable-cytune --disable-fsck --disable-partx --disable-uuidd --disable-mountpoint --disable-fallocate --disable-unshare --disable-nsenter --disable-setpriv --disable-eject --disable-agetty --disable-cramfs --disable-bfs --disable-fdformat --disable-hwclock --disable-wdctl --disable-switch_root --disable-pivot_root --disable-kill --disable-last --disable-utmpdump --disable-mesg --disable-raw --disable-rename --disable-login --disable-nologin --disable-sulogin --disable-su --disable-runuser --disable-ul --disable-more --disable-pg --disable-setterm --disable-schedutils --disable-wall --build="$BUILD_ARCH" --host="$HOST_ARCH" --prefix="$outputdir" --exec-prefix="$outputdir"

这是我的输出：

<...build things including libuuid...>
  CC       fdisks/cfdisk-cfdisk.o
../fdisks/cfdisk.c: In function 'get_string':
../fdisks/cfdisk.c:447:5: warning: implicit declaration of function 'getyx' [-Wimplicit-function-declaration]
../fdisks/cfdisk.c:447:5: warning: nested extern declaration of 'getyx' [-Wnested-externs]
../fdisks/cfdisk.c:447:11: error: 'stdscr' undeclared (first use in this function)
<...>

有没有办法只构建libuuid？

Answer 1

我能够使用以下参数构建libuuid：

--disable-all-programs --enable-libuuid

Answer 2

最简单的方法是从您提供的链接中提取最新的linux-utils tarball，提取其内容，然后修改根级Makefile.am。查找看起来像这样的部分：

include tools/Makemodule.am
include include/Makemodule.am
include lib/Makemodule.am
include libuuid/Makemodule.am
include libblkid/Makemodule.am
include libmount/Makemodule.am
include libsmartcols/Makemodule.am
include libfdisk/Makemodule.am

include schedutils/Makemodule.am
include text-utils/Makemodule.am
include term-utils/Makemodule.am
include login-utils/Makemodule.am
include sys-utils/Makemodule.am
include misc-utils/Makemodule.am
include disk-utils/Makemodule.am

include bash-completion/Makemodule.am

include tests/Makemodule.am

并将其修改为如此（仅保留libuuid条目未注释）：

#include tools/Makemodule.am
#include include/Makemodule.am
#include lib/Makemodule.am
include libuuid/Makemodule.am
#include libblkid/Makemodule.am
#include libmount/Makemodule.am
#include libsmartcols/Makemodule.am
#include libfdisk/Makemodule.am
#
#include schedutils/Makemodule.am
#include text-utils/Makemodule.am
#include term-utils/Makemodule.am
#include login-utils/Makemodule.am
#include sys-utils/Makemodule.am
#include misc-utils/Makemodule.am
#include disk-utils/Makemodule.am
#
#include bash-completion/Makemodule.am
#
#include tests/Makemodule.am

最后，从根目录（您提取的存档），执行以下命令：

autoconf
automake
./configure
make

您可能需要运行automake --add-missing而不是automake和autoreconf --force --install而不是autoconf，具体取决于系统上安装的autotools版本。

现在，只需通过find . -iname "*libuuid.so*"找到您构建的库。

Answer 3

您可以从https://sourceforge.net/projects/libuuid/获取代码并进行编译。这应该只构建libuuid ....

如何从linux utils编译* only * uuid

3 个答案: