Question

我试图制作一个测试三角形是否具有相等边的函数然后打印答案，但我的函数不起作用。有任何想法吗？

 public function typeOfTriangle()
 {

    if ($this->lengthSideOne == $this->lengthSideTwo == $this->lengthBase)
    {echo 'the triangle is equal'}
 );
 }

Answer 1

您无法将==个操作串联起来。您需要使用AND（又名&&）。

像这样：

public function typeOfTriangle()
{
    if ( $this->lengthSideOne == $this->lengthSideTwo && $this->lengthSideTwo == $this->lengthBase ) {
        echo 'the triangle is equal';
    }
}

Answer 2

public function typeOfTriangle（） {

if ($this->lengthSideOne == $this->lengthSideTwo && $this->lengthSideOne == $this->lengthBase)
{echo 'the triangle is equal';}

）; }

Answer 3

试试这个..

public function typeOfTriangle()
 {

    if ($this->lengthSideOne == $this->lengthSideTwo && $this->lengthSideTwo == $this->lengthBase)
    {echo 'the triangle is equal'}
 );
 }

Answer 4

错误是您的括号表示法。

public function typeOfTriangle() {
 if($this->lengthSideOne == $this->lengthSideTwo && $this->lengthSideTwo == $this->lengthBase) {
     echo 'the triangle is equal';
  }
}

如果你使用brances的语法是：

if( ...condition... ) {
   ...do stuff...
}

无支撑条件就像这样工作

if(...condition...)
   ...do stuff...

此处有更多信息：http://www.php.net/manual/en/control-structures.if.php

Answer 5

public function typeOfTriangle()
 {

    if ( $this->lengthSideOne == $this->lengthSideTwo == $this->lengthBase )
    { echo 'the triangle is equal'; }
    // remove this );
 }

Answer 6

您需要将变量传递给函数。

当你打电话时，这样做。（每个数字都是一面）

typeOfTriangle(2,2,4)

然后更改函数的开头以检索此数据并将其分配给$ this，如下所示。

    public function typeOfTriangle($side1, $side2, $side3)
 {

    if ($side1 == $side2 && $side2 == $side3) //this check side 1,2,3 are equal with 2 statements. 
    {echo 'the triangle is equal';}
 }

在php函数上使用if语句

6 个答案: