Flask图像上传到S3只发送HTML

时间:2014-03-11 22:26:32

标签: python amazon-web-services amazon-s3 flask

我正在尝试创建一个将图像上传到Amazon S3存储桶的小应用。我终于能够成功上传某些东西然而当我在S3控制台中检查时,所有上传的内容都是HTML:

<input id="image" name="image" type="file">

烧瓶中:

def s3upload(image, acl='public-read'):
    key = app.config['S3_KEY']
    secret = app.config['S3_SECRET']
    bucket = app.config['S3_BUCKET']

    conn = S3Connection(key, secret)
    mybucket = conn.get_bucket(bucket)

    r = redis.StrictRedis(connection_pool = pool)
    iid = r.incr('image')
    now = time.time()
    r.zadd('image:created_on', now, iid)


    k = Key(mybucket)
    k.key = iid
    k.set_contents_from_string(image)

    return iid

@app.route('/', methods = ['GET', 'POST'])
def index():
    form = ImageForm(request.form)
    print 'CHECKING REQUEST'
    if form.validate_on_submit():
        print 'VALID REQUEST'
        image = form.image.data
        s3upload(image)
    else:
        image = None

    r = redis.StrictRedis(connection_pool = pool)
    last_ten = r.zrange('image:created_on', 0, 9)
    print last_ten
    images = []

    key = app.config['S3_KEY']
    secret = app.config['S3_SECRET']
    bucket = app.config['S3_BUCKET']

    conn = S3Connection(key, secret)
    mybucket = conn.get_bucket(bucket)  


    for image in last_ten:

        images.append(mybucket.get_key(image, validate = False))


    return render_template('index.html', form=form, images=images)

我之前被告知使用set_contents_from_file不正确,而是使用set_contents_from_string

Flask AttributeError: 'unicode' object has no attribute 'tell'

但我觉得这可能是个问题。谢谢你的帮助。

1 个答案:

答案 0 :(得分:1)

只有HTML上传成功,因为您使用的set_contents_from_string方法仅适用于基于文本的文件和图像,因为它们不会被视为字符串。您应该将set_contents_from_file方法用作mentioned in the docs here

将文件对象检索为request.files['image']并将其传递给set_contents_from_file方法。

def s3upload(image, acl='public-read'):
    # do things before
    k.set_contents_from_file(image)
    # do more stuff

@app.route('/', methods = ['GET', 'POST'])
def index():
    form = ImageForm(request.form)
    if form.validate_on_submit():
        s3upload(request.files['image'])
    # do rest of stuff