尝试编写脚本回显所有表格行的列信息,'键'=> '价值'对
我尝试了以下步骤: * 1。 *获取所有列字段 2。运行SELECT查询 3。 echo JSON value Key as(table Fields count)
$table_name = 'Users';
$fieldname=array();
$fieldnames=array();
$fieldnames_C; //fieldNames count
//--------------------------------------------- get colums 'key' array + count;
$result = mysql_query("SHOW COLUMNS FROM {$table_name}");
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_assoc($result)) {
$fieldname = $row['Field'];
array_push($fieldnames, $fieldname); //ARRAY ADD OBJECT
}
$fieldnames_C = count($fieldnames);
echo($fieldnames_C);
}
$users = array();
$query = mysql_query("SELECT * FROM {$table_name}");
//for table count
while ($row = mysql_fetch_array($query))
{
//for columns count
$i = 0;
while($i < $fieldnames_C)
{
$fieldname = $fieldnames[$i];
$users[] = array(
$fieldname => $row[$fieldname]
);
$i++;
}
array_push($users, $fieldname => $row[$fieldname]);
}
echo json_encode(array('response' => $users));
mysql_close($connection);
?>
输出如下:
[{"PID":"79"},{"UserID":"ofir"},{"UserName":"ofir name"},{"UserLat":"32.0511"},{"UserLon":"34.8029"}]
尝试这样的输出: 简单的JsonArray作为表SELECT计数;
[{"PID":"79","UserID":"ofir","UserName":"ofir name","UserLat":"32.0511","UserLon":"34.8029"]
感谢您的回答!
答案 0 :(得分:2)
您的代码可以大大简化:
$data = array();
$result = mysql_query("SELECT * FROM {$table_name}");
while($row = mysql_fetch_assoc($result)) {
$data[] = $row;
}
$field_names = array_keys($data[0]);
当然,只有当你的查询实际返回任何结果时,这才能正常工作,但假设确实如此,这实际上只需复制你正在做的事情。