过滤和分配XML数据有哪些不同的方法 控制。我的应用程序在我使用时显示 数组和循环??
答案 0 :(得分:0)
希望这会有所帮助。在将来,请尝试对您的问题进行更具体的说明。
使用for循环迭代XML的节点,如下所示:
var total:Number = 0;
for each (var property:XML in myXML.item)
{
var q:int = Number(property.@quantity);
var p:Number = Number(property.price);
var itemTotal:Number = q * p;
total += itemTotal;
trace(q + " " + property.menuName + " $" + itemTotal.toFixed(2))
}
trace("Total: $", total.toFixed(2));
您可以使用括号运算符 - (和) - 过滤具有特定元素名称或属性值的元素。请考虑以下XML对象:
var x:XML =
<employeeList>
<employee id="347">
<lastName>Zmed</lastName>
<firstName>Sue</firstName>
<position>Data analyst</position>
</employee>
<employee id="348">
<lastName>McGee</lastName>
<firstName>Chuck</firstName>
<position>Jr. data analyst</position>
</employee>
</employeeList>
以下表达式均有效:
x.employee.(lastName ==
"McGee")--This is the second employee
node.
x.employee.(lastName ==
"McGee").firstName--This is the
firstName property of the second
employee node.
x.employee.(lastName
== "McGee").@id--This is the value of the id attribute of the second
employee node.
x.employee.(@id ==
347)--The first employee node.
x.employee.(@id ==
347).lastName--This is the lastName
property of the first employee node.
x.employee.(@id > 300)--This is an
XMLList with both employee
properties.
x.employee.(position.toString().search("analyst")
> -1)--This is an XMLList with both position properties.
参见http://livedocs.adobe.com/flex/3/html/help.html?content=13_Working_with_XML_04.html 了解更多信息。