提取IP值

Question

有人可以帮忙吗？我是这个网站的新手，也是python的新手。 我必须编写一个脚本来获取IP的最后两个oct并进行一些计算以使它们与端口号匹配。 我一直在撞墙，试图很难获得IP的最后两个值。 任何帮助都会很棒。这是我的代码：

import sys
import re

    t= open('fileD.txt','r')
    t = t.readline()
    s = t.split(";")
    holder = []
    wordlist = {}
    print s

    for c in s:
        wordlist[c.split()[0]] = c.split()
        print c
        with open('filex.txt','w') as x:
            x = x.write(c)

    x = open('filek.txt','w')
    with open ('filex.txt', 'r') as f:
        column = 0
        for line in f:
            if not re.match('@', line):
                line = line.strip()
                sline = line.split()
                x.write(sline[column] + '\n')
    x.close()
    sys.exit(0)

这是fileD.txt：

的内容

99413 ;199.189.17.13 9999
99413 ;199.189.17.13 9999
99414 ;199.189.17.14 9999
99414 ;199.189.17.14 9999
99414 ;199.189.17.14 9999
99415 ;199.189.17.15 9999
99415 ;199.189.17.15 9999
99415 ;199.189.17.15 9999

所以，我需要取.17和.10并将它们放入计算中以生成99415，这是一个端口。

Answer 1

你可以这样做：

file = open("fileD.txt","r")

for line in file: # for example, first line
    ipparts = line.split()[1][1:].split(".") # list as ["199","189","17","13"]
    thirdgroup = ipparts[2] # "17"
    forthgroup = ipparts[3] # "13"
    # make here what you want with those values.

file.close()

Answer 2

您可以使用列表理解：

with open('fileD.txt') as f:
    last_two_nums = [line.split()[1][-5:].split('.') for line in f] # [['17', '13'], ['17', '13'], ...]

或

with open('fileD.txt') as f:
    for line in f:
        last_two_nums = line.split()[1][-5:].split('.') # gives for ex: ['17', '13']
        # do what you've got to do here

您可以通过last_two_nums[0]或last_two_nums[1]访问它们 在进行任何计算之前，请确保将它们从字符串转换为数字 使用int()或float()