我做了一个按钮,这是一段代码(bootstrap):
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这段mysql代码,其中包含一些链接:
<?php
$con=mysqli_connect("localhost","admin","admin133","kernel");
if (mysqli_connect_errno())
{
echo "Error bij connecten: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM hack ORDER BY ID DESC ");
echo "<table border='0'>
<tr>
<th>Name</th>
<th>Status</th>
<th>Retepreter</th>
<th>Kwikie</th>
<th>Nevermind</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['kakatoeee'] . "</td>";
echo "<td>" . $row['kakatoe2'] . "</td>";
echo "<td>" . $row['kakatoe'] . "</td>";
echo "<td>" . $row['papaja'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
现在,我的问题是,如何使链接连接到引导按钮? (对不起,如果我有点不清楚,我是荷兰人,很难输入英文)
papaja,kakatoe等是我的http!