问题
我有一个从PHPExcel通过以下
返回的数组<?php
require_once 'PHPExcel/Classes/PHPExcel/IOFactory.php';
$excelFile = "excel/1240.xlsx";
$objReader = PHPExcel_IOFactory::createReader('Excel2007');
$objPHPExcel = $objReader->load($excelFile);
foreach ($objPHPExcel->getWorksheetIterator() as $worksheet) {
$arrayData[$worksheet->getTitle()] = $worksheet->toArray();
}
print_r($arrayData);
?>
返回:
Array
(
[Films] => Array
(
[0] => Array
(
[0] => Name
[1] => Rating
)
[1] => Array
(
[0] => Shawshank Redemption
[1] => 39
)
[2] => Array
(
[0] => A Clockwork Orange
[1] => 39
)
)
[Games] => Array
(
[0] => Array
(
[0] => Name
[1] => Rating
)
[1] => Array
(
[0] => F.E.A.R
[1] => 4
)
[2] => Array
(
[0] => World of Warcraft
[1] => 6
)
)
)
我想拥有的是
Array
(
[Films] => Array
(
[0] => Array
(
[Name] => Shawshank Redemption
[Rating] => 39
)
[1] => Array
(
[Name] => A Clockwork Orange
[Rating] => 39
)
)
[Games] => Array
(
[0] => Array
(
[Name] => F.E.A.R
[Rating] => 4
)
[1] => Array
(
[Name] => World of Warcraft
[Rating] => 6
)
)
)
数组名称(电影,游戏)取自工作表名称,因此数量可以是可变的。第一个子数组将始终包含密钥名称,例如电影[0]和游戏[0]及其数量可以变化。我(我想)知道我需要做类似下面的事情,但我不知所措。
foreach ($arrayData as $value) {
foreach ($value as $rowKey => $rowValue) {
for ($i=0; $i <count($value) ; $i++) {
# code to add NAME[n] as keys
}
}
}
我在这里进行了广泛的搜索,如果是重复的话我将删除它。
感谢任何输入
答案 0 :(得分:3)
尝试
$result= array();
foreach($arr as $key=>$value){
$keys = array_slice($value,0,1);
$values = array_slice($value,1);
foreach($values as $val){
$result[$key][] = array_combine($keys[0],$val);
}
}
请参阅演示here
答案 1 :(得分:2)
您可以使用嵌套的array_map
来电。不知怎的,这样:
$result = array_map(
function ($subarr) {
$names = array_shift($subarr);
return array_map(
function ($el) use ($names) {
return array_combine($names, $el);
},
$subarr
);
},
$array
);
答案 2 :(得分:1)
我认为这样做:
foreach($arrayData as $key => $array){
for($i=0; $i<count($array[0]); $i++){
$indexes[$i]=$array[0][$i];
}
for($i=1; $i<count($array); $i++){
for($j=0; $j<count($array[$i]); $j++){
$temp_array[$indexes[$j]]=$array[$i][$j];
}
$new_array[$key][]=$temp_array;
}
}
print_r($new_array);
编辑:测试并更新代码,有效...
答案 3 :(得分:1)
这样的事情应该有效:
$newArray = array();
foreach ($arrayData as $section => $list) {
$newArray[$section] = array();
$count = count($list);
for ($x = 1; $x < $count; $x++) {
$newArray[$section][] = array_combine($list[0], $list[$x]);
}
}
unset($arrayData, $section, $x);
答案 4 :(得分:1)
可能有点迟到的答案,但它看起来更像是你尝试过的解决方案
//Films,Games // Row Data
foreach ($arrayData as $type => $value)
{
$key1 = $value[0][0]; // Get the Name Key
$key2 = $value[0][1]; // Get the Rating Key
$count = count($value) - 1;
for ($i = 0; $i < $count; $i++)
{
/* Get the values from the i+1 row and put it in the ith row, with a set key */
$arrayData[$type][$i] = array(
$key1 => $value[$i + 1][0],
$key2 => $value[$i + 1][1],
);
}
unset($arrayData[$type][$count]); // Unset the last row since this will be repeated data
}