我使用了bootstrap内联表单。这是代码:
<form class="form-inline" action="php/signup.php" method="post">
<div class="form-group">
<label class="sr-only" for="firstname">First name</label>
<input type="text" required class="form-control" id="exampleInputEmail2" name="firstname" placeholder="First name">
</div>
<div class="form-group">
<label class="sr-only" for="middlename">Middle name</label>
<input type="text" class="form-control" id="exampleInputEmail2" name="middlename" placeholder="Middle name">
</div>
<div class="form-group">
<label class="sr-only" for="lastname">Last name</label>
<input type="text" required class="form-control" id="exampleInputPassword2" name="lastname" placeholder="Last name">
</div>
<br/>
<br/>
<div class="form-group">
<label class="sr-only" for="username">User name</label>
<input type="text" required class="form-control" id="exampleInputPassword2" name="username" placeholder="Desired user name">
</div>
<br/>
<br/>
<div class="form-group">
<label class="sr-only" for="password">Password</label>
<input type="password" required class="form-control" id="exampleInputPassword2" name="password" placeholder="Password">
</div>
<br/>
<br/>
<div class="form-group">
<label class="sr-only" for="repassword">Re enter password</label>
<input type="password" required class="form-control" id="exampleInputPassword2" name="repassword" placeholder="Re enter password">
</div>
<br/>
<br/>
<div class="form-group">
<input type="email" required class="form-control" id="exampleInputPassword2" name="email" placeholder="E-mail address">
</div>
<br/>
<br/>
<button type="submit" name="btnSubmit"> Sign up</button>
</form>
我也是提交表单数据的PHP后端:
<?php
session_start();
include("connect_to_mysql.php");
if(isset($_POST("btnSubmit")))
{
$firstname = mysql_real_escape_string($_POST("firstname"));
$middlename = mysql_real_escape_string($_POST("middlename"));
$lastname = mysql_real_escape_string($_POST("lastname"));
$username = mysql_real_escape_string("username");
$password = mysql_real_escape_string("password");
// check the re entered password using jquery on the client machine itself
$email = mysql_real_escape_string("email");
/*firstname varchar(255),
middlename varchar(255) NOT NULL,
lastname varchar(255) NOT NULL,*/
$query = "create table if not exists authenlist(
id int NOT NULL AUTO_INCREMENT,
username varchar(255) NOT NULL,
password varchar(255) NOT NULL,
PRIMARY KEY (id))";
$i = mysql_query($query) or die("authentication table not created");
if($i)
{
$query = "select * from authenlist where username='$username'";
$o = mysql_query($query) or die("query not executed");
if($o)
{
if(mysql_num_rows($o) == 0)
{
$query = "insert into authenlist values('', '$username', '$password')";
$_SESSION['username']=$username;//to register user
header("location:home.php");
exit();
}
else
{
header("status: 404 not found");
}
}
}
}
?>
当我尝试提交表单时,总会出现致命错误:致命错误:无法在第4行的C:\ wamp \ www \ the_unknown \ php \ signup.php中的写入上下文中使用函数返回值。< / p>
我无法理解表单提交过程中的错误。 我迫切需要这种形式,我真的需要它来工作。 请有人帮我解决我面临的问题。 提前谢谢。
答案 0 :(得分:3)
$_POST("btnSubmit")
错了
使用
$_POST["btnSubmit"]
它是任何数组