Question

由于设置factory_girl的困难，我正在进行一些测试失败。我有一个JOB类和一个TEMPLATE类。还有一个PROVIDER用户类。作业属于JOB和TEMPLATE。但是，我当前的工厂分别指定了提供者和模板。

这一次突破：

  expect { post :create, job: attributes_for(:job, provider_id: provider.id) }.to change(Job,:count).by(1)

这一项工作（手动定义）：

  expect { post :create, job: attributes_for(:job, provider_id: provider.id, template_id: create(:template, provider_id: provider.id) ) }.to change(Job,:count).by(1)

有没有办法设置工厂将模板自动创建为属于提供者？

  factory :job do
    provider
    template
  end

  factory :template do
    template_type { Faker::Lorem.word }
    template_text { Faker::Lorem.paragraph(3) }
  end

Answer 1

根据我的描述，模板还应该引用创建的提供程序。你可以写这样的东西，比如

factory :job do
  provider

  after(:build) do |job|
    job.template = build(:template, provider: job.provider)
  end
end

您可以在https://github.com/thoughtbot/factory_girl/blob/master/GETTING_STARTED.md#callbacks

中了解相关信息

Answer 2

要处理不返回关联的attributes_，您可以定义自己的attributes_for，包括这些。我曾经写过一个定制的，非常复杂的方法，包括所有“可访问”的关联。我会在这里包含它，以防你想使用它

# In contrast with "attributes_for", "attributes_for_incl_associations" does return attributes 
# for accessible associations as well
# Inspired by: http://stackoverflow.com/questions/10290286/factorygirl-why-does-attributes-for-omit-some-attributes
def attributes_for_incl_associations(*args)
  obj = FactoryGirl.build(*args); klass = obj.class

  # Find all accessible attributes in object's class
  if defined? controller and controller.current_user and klass.active_authorizers.include? controller.current_user.role
    accessible = klass.accessible_attributes(controller.current_user.role)
  else
    accessible = klass.accessible_attributes(:default)
  end

  # Find all associations in object's class
  associations = klass.reflect_on_all_associations(:belongs_to).map { |a| "#{a.name}_id" }

  # Find all accessible associations in the created object's attributes
  accessible_associations = obj.attributes.delete_if do |k, v| 
    !accessible.include?(k) || !associations.member?(k) 
  end

  # Remove all attributes from FactoryGirl attributes that are not accessible
  factory_attributes = FactoryGirl.attributes_for(*args).delete_if do |k, v|
    !accessible.include?(k)
  end

  # Merge FactoryGirl attributes with accessible associations
  factory_attributes.merge(accessible_associations.symbolize_keys)
end

factory_girl新实例继承关联类的父ID

2 个答案: