Question

我必须得到每个查询的结果

第一次查询：

SELECT  [xcv],  COUNT( * ) AS Total
  FROM [my_table]  
 GROUP BY [xcv]

第二个查询：

SELECT [xcv],  COUNT( * ) AS Total
      FROM [my_table]   
    WHERE=[result]='ok'
    GROUP BY [xcv]

我想要做的是获得 - ＆gt;的值[（first_query / second query）* 100]

我想在我的表格中找到每个[xcv]的结果......

任何想法我怎么做？

谢谢大家

Answer 1

SELECT t1.[xcv], 
       (t1.total/t2.total)*100
  FROM (SELECT [xcv],  
               COUNT( * ) AS Total
          FROM [my_table]  
        GROUP BY 
               [xcv]
        ) t1 JOIN (
                   SELECT [xcv], 
                          COUNT( * ) AS Total
                     FROM [my_table]   
                    WHERE [result]='ok'
                    GROUP BY 
                          [xcv]
                   ) t2
                  ON t1.[xcv]=t2.[xcv]

我还从=删除了WHERE=[result]='ok'个符号 - 我认为您输了错误。

Answer 2

一个查询：

SELECT [xcv],
       (SUM(CASE 
                 WHEN [result] = 'ok' 
                      THEN 1 
                      ELSE 0 
                 END
           )/COUNT( * )
        ) * 100
  FROM [my_table]
GROUP BY [xcv]

如何对两个查询的结果进行数学运算

2 个答案: