我正在尝试在单行中合并下面的查询,以便结果出现在同一行中。 company_id在两个查询中都很常见。 需要建议???
第一次查询:
select c.id as company_id,
AVG(DATEDIFF(cdr.created_at,cd.send_to_brand_date))
as Avg_time_taken_for_first_comment
from
complaint3 c3,
complaint3_details cd,
complaint3_diary cdr,
company c
where c3.id=cd.complaint_id
and cd.send_to_brand=1
and c.id=c3.company_id
and cdr.complaint_id=c3.id
and cdr.id in(
select min(id)
from complaint3_diary
where complaint_id=c3.id
and user_id IN(
select id from user3
where user_type=2))
and c.id=351
and c3.created_at>='2014-01-01'
and c3.created_at<='2014-01-30'
and cdr.created_at>='2014-01-01'
and cdr.created_at<='2014-01-30'
第二次质疑:
select c.id as company_id,
avg(datediff(cs.created_at,cd.send_to_brand_date))
as avg_time_closure
from complaint3 c3,
complaint3_status cs,
complaint3_details cd,
company c
where c3.id=cs.complaint_id
and c3.id=cd.complaint_id
and c.id=c3.company_id
and cs.complaint_id=c3.id
and cd.send_to_brand=1
and cs.id IN(
select max(id)
from complaint3_status
where complaint_id=c3.id
and status_type IN(2)
)
and cs.status_value=2
and c.id=272
and cs.created_at>='2014-01-01'
and cs.created_at<='2014-01-30'
答案 0 :(得分:0)
SELECT *
FROM (<1st query>) AS q1
JOIN (<2nd query>) AS q2
ON q1.company_id = q2.company_id
答案 1 :(得分:0)
您可以将两个Queryes用作子查询
SELECT(第一个查询),(第二个查询)FROM&lt;&lt;任何表&gt;&gt;