Question

我有这个选择

SELECT  
        products.prod_name, SUM(beg_inv - end_inv)  AS inv,
        MONTH(task_date) MONTH
    FROM    performances 
        INNER JOIN tasks 
        ON performances.task_id = tasks.task_id
        INNER JOIN people
        ON people.person_id = tasks.emp_id
        INNER JOIN products
        ON performances.prod_id = products.prod_id
    WHERE   YEAR(task_date) = '2013'
    GROUP BY performances.prod_id, MONTH(task_date)
    ORDER BY MONTH(task_date), prod_name

及其出局是：

Prod name   inv month
Product 1   5   3
Product 1   10  5

我想像这样传播它：

Product Name    January February    March   April   May June    July    August  September   October November    December
Product 1                               5           10

是否可以不必进行Pivot而只是选择？

Answer 1

只需在SQL中执行此操作：

SELECT products.prod_name,
       SUM(case when MONTH(task_date) = 1 then beg_inv - end_inv end)  AS January,
       SUM(case when MONTH(task_date) = 2 then beg_inv - end_inv end)  AS February,
       SUM(case when MONTH(task_date) = 3 then beg_inv - end_inv end)  AS March,
       . . .  
FROM    performances 
        INNER JOIN tasks 
        ON performances.task_id = tasks.task_id
        INNER JOIN people
        ON people.person_id = tasks.emp_id
        INNER JOIN products
        ON performances.prod_id = products.prod_id
WHERE   YEAR(task_date) = 2013
GROUP BY products.prod_name,
ORDER BY products.prod_name,;

请注意，这还需要对GROUP BY和ORDER BY子句进行细微更改。

SQL选择将行数据传播到列

1 个答案: