Question

所以我只是想制作一只易飞鸟的复制品。但是，我想知道如何实现鸟皮瓣？我想过使用方法

- (void) touchesBegan: (NSSet *) touches withEvent: (UIEvent *) event

但是我注意到如果你使用这种方法并按下屏幕，鸟会不断拍打。我只是想在点击屏幕时让鸟儿翻动，如果我按下屏幕，它的行为方式与点击一次相同。

是否有使用这类行为的类引用？

Answer 1

要获取点击事件，您可以使用Apple提供的UITapGestureRecognizer。只需启动它，根据您的要求设置参数，并将其添加到您想要记录水龙头的视图中。

    UITapGestureRecognizer *tap = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleTap:)];
    tap.numberOfTapsRequired = 1;
    tap.numberOfTouchesRequired = 1;
    [demoView addGestureRecognizer:tap]; // The gesture recognizer is being added to demoView
    [tap release]; // In case of not using ARC

定义你在初始化中提到的选择器。

- (void)handleTap:(UITapGestureRecognizer *)recognizer{
         // Handle the tapping here
}

Answer 2

我非常沮丧，因为我不能像Flappy Bird那样画出地面......我尝试使用这种方法：

private void drawGround(){  
for(Rectangle mRectangleGroundHelper : mArrayGround){
    if(spawnGround & mRectangleGroundHelper.x<0){ // spawn Ground if the actual ground.x + ground.width() is smaller then the display width.
        mArrayGround.add(mRectangleGroundHelper);
        spawnGround = false;
    }
}
for(Rectangle mRectangleGroundHelper : mArrayGround){
    if(mRectangleGroundHelper.x < -mTextureGround.getWidth()){ // set boolean to true, if the actual ground.x completely hide from display, so a new ground can be spawn
        spawnGround = true;
    }
}

for(Rectangle mRectangleGroundHelper : mArrayGround){ // move the ground in negative x position and draw him...
    mRectangleGroundHelper.x-=2;
    mStage.getSpriteBatch().draw(mTextureGround, mRectangleGroundHelper.x, mRectangleGroundHelper.y);
}

}

您可以在here

下载应用

你怎么做飞扬的鸟皮瓣？

2 个答案: