Question

我使用以下代码调用ashx页面。但它不适合我。我把我的代码放在这里。我总是收到错误消息消息＆＃34;请求失败＆＃34;。请帮帮我..

<script type="text/javascript">
        function CallLoginHandler(user, pass) {
            alert(user);//Got value
            alert(pass);//Got Value
            $(function(){
            $.ajax({
                type: "POST",
                url: "../handler/JQGridHandler.ashx?MainPage=GetUserDetails&Type=2&user=" + user + "&pass=" + pass + "",
                contentType: "application/json; charset=utf-8",
                dataType: "json",
                success: OnComplete,
                error: OnFail
            });

            return false;
            });
        }

        function OnComplete(result) {
            alert([result.Id, result.Name, result.Age, result.Department]);
        }
        function OnFail(result) {          
            alert('Request Failed');
        }

    </script>

Answer 1

删除这些行：

 $(function(){  // <----remove this

        return false; // and this
        });  // and this too

更新此功能：

function CallLoginHandler(user, pass) {
        $.ajax({
            type: "POST",
            url: "../handler/JQGridHandler.ashx", // updated url
            data: { // pass your data like this since type is post
                 MainPage:"GetUserDetails",
                 Type:2,
                 user:user,
                 pass:pass
            },
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            success: OnComplete,
            error: OnFail
        });
    }

并且您的网址也不正确：

url: "../handler/JQGridHandler...... + pass + "", 
// --here you have a blank `""` after pass-----^

并且因为您的type: "post"所以您可以传递这样的数据：

data: {
  MainPage:"GetUserDetails",
  Type:2,
  user:user,
  pass:pass
},

Answer 2

将您的字符串分隔为要编码的javascript对象，并根据您的内容类型将其作为JSON发送到服务器。另外，在函数调用中删除$(function(){，这里没用。

$.ajax({
    type: "POST",
    url: "../handler/JQGridHandler.ashx';
    contentType: "application/json; charset=utf-8",
    dataType: "json",
    data: {
        MainPage: 'GetUserDetails',
        Type: 2,
        user: user,
        pass: pass
    }
    success: OnComplete,
    error: OnFail
});

如果这不起作用，则问题可能是以下之一：

网址错误
服务器正在评估GET而不是POST请求
服务器期望application/x-www-form-urlencoded，但您已宣布为json
您有路由问题

Answer 3

注意：请勿发送您的用户并传入查询字符串。

function CallLoginHandler(user, pass) {
$.ajax({
        type: "POST",
        url: "../handler/JQGridHandler.ashx",
        data: {
                  MainPage: 'GetUserDetails',
                  Type: 2,
                  user: user,
                  pass: pass
        },
        // DO NOT SET CONTENT TYPE to json
        // contentType: "application/json; charset=utf-8",
        // DataType needs to stay, otherwise the response object
        // will be treated as a single string
        dataType: "json",
        success: OnComplete,
        error: OnFail
    });

}）; }

您的handler.ashx文件

using System;
using System.Web;
using Newtonsoft.Json;

public class Handler : IHttpHandler
{
    public void ProcessRequest(HttpContext context)
    {
        context.Response.ContentType = "text/plain";

        string user= context.Request.Form["user"];
        //.....  
        var wrapper = new { d = myName };
        // in order to use JsonConvert you have to download the
        // Newtonsoft.Json dll from here  http://json.codeplex.com/
        context.Response.Write(JsonConvert.SerializeObject(wrapper));
    }

    public bool IsReusable
    {
       get
       {
            return false;
       }
    }
}

source

Jquery对ashx没有工作的事件没有解雇

3 个答案: