Question

它只显示一个我要显示2个图像的图像我想显示几个图像，但有其他表信息，但首先我想知道如何显示多个图像

 <?php
 $stmt = $mysqli->prepare("SELECT link FROM images WHERE ID = 1");
$stmt->bind_param("i", $ID);
$stmt->execute();
$stmt->bind_result($link);
$stmt->fetch();

?>
<img id="result_img" src="<?php echo $link; ?>" /> 


<?php
$stmt = $mysqli->prepare("SELECT link FROM images WHERE ID = 2");
$stmt->bind_param("i", $ID);
$stmt->execute();
$stmt->bind_result($link);
$stmt->fetch();

?>
 <img id="result_img" src="<?php echo $link; ?>" />

Answer 1

试试这个，

 $stmt = $mysqli->prepare("SELECT link FROM images WHERE ID = ?");
 $stmt->bind_param("i", $ID);
 $stmt->execute();
 $stmt->bind_result($link);
 $stmt->fetch();
 $stmt->store_result();

 if( $stmt->num_rows > 0 )
 {
    while( $stmt->fetch() ) 
    {
       echo '<img id="result_img" src="'.$link.'" />';
    }
 }

 /* for second link just use already prepared query */
 $stmt->bind_param("i", $ID2);
 $stmt->execute();
 $stmt->bind_result($link);
 $stmt->fetch();
 $stmt->store_result();

 if( $stmt->num_rows > 0 )
 {
    while( $stmt->fetch() ) 
    {
       echo '<img id="result_img" src="'.$link.'" />';
    }
 }

为什么这不能显示2个图像

1 个答案: