我正在将旧的遗留PHP系统转换为Flask + SQLAlchemy,并且想知道如何构建以下内容:
我有一个模特:
class Invoice(db.Model):
paidtodate = db.Column(DECIMAL(10,2))
fullinvoiceamount = db.Column(DECIMAL(10,2))
invoiceamount = db.Column(DECIMAL(10,2))
invoicetype = db.Column(db.String(10))
acis_cost = db.Column(DECIMAL(10,2))
我需要运行的查询是:
SELECT COUNT(*) AS the_count, sum(if(paidtodate>0,paidtodate,if(invoicetype='CPCN' or invoicetype='CPON' or invoicetype='CBCN' or invoicetype='CBON' or invoicetype='CPUB' or invoicetype='CPGU' or invoicetype='CPSO',invoiceamount,
fullinvoiceamount))) AS amount,
SUM(acis_cost) AS cost, (SUM(if(paidtodate>0,paidtodate,invoiceamount))-SUM(acis_cost)) AS profit FROM tblclientinvoices
是否有SQLAlchemyish方法来构造此查询? - 我尝试用SQlAlchemy谷歌搜索Mysql IF的声明,但画了空白。
非常感谢!
答案 0 :(得分:7)
使用func
(documentation)生成SQL函数表达式:
qry = select([
func.count().label("the_count"),
func.sum(func.IF(
Invoice.paidtodate>0,
Invoice.paidtodate,
# @note: I prefer using IN instead of multiple OR statements
func.IF(Invoice.invoicetype.in_(
("CPCN", "CPON", "CBCN", "CBON", "CPUB", "CPGU", "CPSO",)
),
Invoice.invoiceamount,
Invoice.fullinvoiceamount)
)
).label("amount"),
func.sum(Invoice.acis_cost).label("Cost"),
(func.sum(func.IF(
Invoice.paidtodate>0,
Invoice.paidtodate,
Invoice.invoiceamount
))
- func.sum(Invoice.acis_cost)
).label("Profit"),
],
)
rows = session.query(qry).all()
for row in rows:
print row