我有以下数据:
| ID | Date | Code |
--------------------------
| 1 | 26/02/14 | 10 |
| 1 | 25/02/14 | 11 |
| 1 | 24/02/14 | 10 |
| 2 | 25/02/14 | 13 |
| 2 | 24/02/14 | 11 |
| 2 | 23/02/14 | 10 |
我想要的是按ID字段分组并从日期字段(即最近的字段)返回最大值。所以最终的结果应该是这样的:
| ID | Date | Code |
--------------------------
| 1 | 26/02/14 | 10 |
| 2 | 25/02/14 | 13 |
似乎如果我想在同一个查询中显示“代码”字段,我也必须对它进行分组或聚合......这是有道理的,因为在该字段之后可能会有多个值其他人被分组/聚合(即使在这种情况下不会)。
我认为我可以通过在子查询中仅对这些字段执行GroupBy和Max来处理此问题,然后在该子查询上进行连接以引入我不希望分组或聚合的“代码”字段:
SELECT Q.ID, Q.MaxOfDate, A.Code
FROM
(SELECT B.ID, Max(B.Date) As MaxOfDate
FROM myTable As B
GROUP BY B.ID) As Q
LEFT JOIN myTable As A ON Q.ID = A.ID;
这不起作用,因为它仍然只给我我开始的原始记录数。
如何使用不一定要分组/聚合的字段进行分组和聚合?
答案 0 :(得分:1)
我接受的答案的替代方案:
SELECT Q.ID, Q.MaxOfDate, A.Code
FROM
(SELECT B.ID, Max(B.Date) As MaxOfDate
FROM myTable As B
GROUP BY B.ID) As Q
LEFT JOIN myTable As A ON (Q.ID = A.ID) AND (A.Date = Q.MaxOfDate);
需要在日期字段和ID字段上执行LEFT JOIN
。
答案 1 :(得分:0)
如果您希望CODE与Max Date相关联,则必须使用带有top 1的子查询,如下所示:
SELECT B.ID, Max(B.Date) As MaxOfDate,
(select top 1 C.Code
from myTable As C
where B.ID = C.ID
order by C.Date desc, C.Code) as Code
FROM myTable As B
GROUP BY B.ID