我正在C#上编写一个Console应用程序,我希望在连续显示文本时播放声音。这就是我所做的:
static SoundPlayer typewriter = new SoundPlayer("typewriter");
static public void print(string str, int delay)
{
Thread skipThread = new Thread(skipText);
typewriter.PlayLooping();
textgap = delay;
foreach (char c in str)
{
Console.Write(c);
if (textgap != 0)
Thread.Sleep(textgap);
}
typewriter.Stop();
}
typewriter.wav
已导入.cs
文件旁边的项目,我选择了copy always
。当我运行此代码时,在开始播放声音Please be sure a sound file exists at the specified location.
时会弹出错误
这有什么不对?
编辑: 根据Kevin J的回答将我的代码更改为以下内容。
static SoundPlayer typewritter;
public static void Load()
{
Assembly assembly;
assembly = Assembly.GetExecutingAssembly();
typewritter = new SoundPlayer(assembly.GetManifestResourceStream
("typewriter"));
}
我也应该使用路径Environment.CurruntDirectory + "typewriter"
,但没有任何改变。
答案 0 :(得分:3)
找出问题:我只需要设置SoundLocation
实例的SoundPlayer
属性:
SoundPlayer typewriter = new SoundPlayer();
typewriter.SoundLocation = Environment.CurrentDirectory + "/typewriter.wav";
答案 1 :(得分:2)
这里有些东西可以帮助你(请注意这个代码适用于winforms应用程序,但你应该能够转换为控制台应用程序。只需研究代码以了解它是如何工作的)你基本上会添加.wav文件作为程序的“资源”。然后,您的程序可以访问.wav文件并播放它:
using System.Reflection;
using System.IO;
using System.Resources;
using System.Media;
using System.Diagnostics;
namespace Yournamespace
{
public partial class Form2 : Form
{
public Form2()
{
InitializeComponent();
}
private void Form2_Load(object sender, EventArgs e)
{
Assembly assembly;
Stream soundStream;
SoundPlayer sp;
assembly = Assembly.GetExecutingAssembly();
sp = new SoundPlayer(assembly.GetManifestResourceStream
("Yournamespace.Dreamer.wav"));
sp.Play();
}
}
}
答案 2 :(得分:0)
例如,如果您的声音位于“资产”文件夹中,则子文件夹“ SoundClips”就是这样。
var soundLocation = Environment.CurrentDirectory + @"\Assets\SoundClips\";
SoundPlayer player = new SoundPlayer
{
SoundLocation = soundLocation + "typewriter.wav",
};
确保将文件属性设置为:
构建操作-内容
复制到输出目录-如果较新则复制