Question

我正在为我的网站开发登录系统，但是当我将所有信息（用户，密码，电子邮件）插入到sigm-up函数的数据库中时，它将所有变量设置为0.我知道这不是传递变量的问题，因为我已经回应了用户名和密码，他们就是他们想要的。我的注册页面的代码如下：

<?php

include '../includes/conn.php';
include 'salt.php';

if($_POST['signup']){

    $user = $_POST['user'];
    $pass = $_POST['pass'];
    $cpass = $_POST['cpass'];
    $email = $_POST['email'];

        if($pass == $cpass){
            $hpass = create_hash($pass);

            $query = $conn->prepare("INSERT INTO Users (Name, Password, Email) VALUES (?, ?, ?)");
        $query->bind_param('sss', $user, $hpass, $email);
        $query->execute();

            if($query){
                $msg = 'Account created successfully, please check your email to verify it.';
            }else{
                $msg = 'There was an error creating your account: ' . $conn->error . ', please try again later';
            }

            //echo $user . ' ' . $pass . ' ' . $hpass . ' ' . $email;

        }else{
            $msg = 'Passwords do not match.';
        }
}

?>

<html>

    <head>

        <title>DiscFire Softworks - Login test</title>

        <link rel="stylesheet" type="text/css" href="../includes/ie-styles.css">

        <style type="text/css">

            @import url('../includes/styles.css');

        </style>

    </head>

    <body>

        <div class="body">

            <img src="../images/header.jpg" />

            <div class="navbar">

                <?php

                    $query = $conn->prepare("SELECT Name FROM pages ORDER BY ID asc");
                    $query->execute();
                    $query->bind_result($name);

                    while($query->fetch())
                    {
                        echo '<a href="/?page=' . $name . '">' . $name . '</a>';
                    }

                ?>

            </div>

            <?php
                echo '<p>' . $msg . '</p>';
            ?>

            <form method="POST" action="index.php" id="sign-up">

                <input type="hidden" name="signup" value="1"/>
                <label for="user">Username: </label>
                <input type="text" style="width: 30%; margin-left: 59px;" name="user"></textarea>
                <br />
                <label for="pass">Password: </label>
                <input type="password" style="width: 30%; margin-left: 60px;" name="pass"></textarea>
                <br />
                <label for="cpass">Confirm Password: </label>
                <input type="password" style="width: 30%; margin-left: 1px;" name="cpass"></textarea>
                <br />
                <label for="user">Email: </label>
                <input type="text" style="width: 30%; margin-left: 90px;" name="email"></textarea>
                <input type="submit" />
            </form>

        </div>

    </body>

</html>

以下是@Prix要求的SQL结构：

http://prntscr.com/2vsmjv

提前致谢！

Answer 1

似乎我将行设置为整数...哎呀。

PHP mysqli在插入表时将变量设置为0

1 个答案: