Question

对于elementtree来说非常新，所以我正在尝试为xbmc解析tv addon的xml文件。下面是我遇到问题的代码。我认为我的xpath不正确，占位符没有处理该属性！

这是我正在使用的xml文件 - http://services.tvrage.com/myfeeds/episode_list.php?key=ag6txjP0RH4m0c8sZk2j&sid=2930

    seasonnum = root2.findall("/Show/Episodelist/Season[@no='%s']/episode/seasonnum" % (season))


        import xml.etree.ElementTree as ET
        import urllib            
        tree2 = ET.parse(urllib.urlopen(url))
        root2 = tree2.getroot()
        seasonnum = tree2.findall("./Episodelist/Season[@no='%s']/episode/seasonnum" % '1')
        print seasonnum

SyntaxError：期望路径分隔符（[]是我得到的

Answer 1

使用ElementTree：

>>> from xml.etree import ElementTree
>>> import urllib2
>>> url = 'http://services.tvrage.com/myfeeds/episode_list.php?key=ag6txjP0RH4m0c8sZk2j&sid=2930'
>>> request = urllib2.Request(url, headers={"Accept" : "application/xml"})
>>> u = urllib2.urlopen(request)
>>> tree = ElementTree.parse(u)
>>> rootElem = tree.getroot()
>>> [s.text for s in rootElem.findall('.//Season[@no="2"]/episode/seasonnum')]
['01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12', '13', '14', 
 '15', '16', '17', '18', '19', '20', '21', '22']

Answer 2

根据xml.etree.ElementTree documentation - XPath support：

此模块为XPath表达式提供有限的支持在树中定位元素。目标是支持一小部分缩写语法;完整的XPath引擎超出了范围模块。

您可能需要像lxml这样的第三方库来使用XPath。

示例：

>>> import lxml.etree
>>>
>>> url = 'http://services.tvrage.com/myfeeds/episode_list.php?key=ag6txjP0RH4m0c8sZk2j&sid=2930'
>>> tree = lxml.etree.parse()
>>> tree.xpath("/Show/Episodelist/Season[@no='%s']/episode/seasonnum/text()" % 1)
['01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12']

<强>更新

要使用lxml.etree.ElementTree，应略微修改xpath：

>>> import urllib
>>> import xml.etree.ElementTree as ET
>>>
>>> f = urllib.urlopen(url)
>>> tree = ET.parse(f)
>>> [e.text for e in tree.findall("./Episodelist/Season[@no='%s']/episode/seasonnum" % 1)]
['01', '02', '03', '04', '05', '06', '07', '08', '09', '10', '11', '12']

Answer 3

我试过你的例子，但它确实有效。这是一个精简的完整版本：

import urllib
import xml.etree.ElementTree as ET

url = 'http://services.tvrage.com/myfeeds/episode_list.php?key=ag6txjP0RH4m0c8sZk2j&sid=2930'
tree = ET.parse(urllib.urlopen(url))
seasons = tree.findall("./Episodelist/Season[@no='%s']/episode/seasonnum" % '1')

for s in seasons:
    print s.text

我能想到的唯一问题是，你以某种方式下载了一个部分XML文档 - 不太可能，但我不知道任何其他解释。请注意，上述脚本取自您的问题。我只添加了for循环。

Answer 4

    import xml.etree.ElementTree as ET
    import urllib
    content = urllib.urlopen(url).read()
    tree2 = ET.fromstring(content)
    tvrage_seasons = tree2.findall('.//Season' )

由于某种原因，在xbmc Elementtree中必须有一个错误或某些东西不能使它工作。但这对我来说很有用！

xpath为python问题

4 个答案: