我有一个程序,它为每个用户聚合下载总数,总计下载数据总和为kb。
local table = {}
table[userID] = {5, 23498502}
我的目标是printTable
函数的输出将按照下载的kb数量生成按降序排序的整个用户列表v[2]
local aUsers = {}
...
function topUsers(key, nDownloads, totalSize)
if aUsers[key] then
aUsers[key][1] = aUsers[key][1] + nDownloads
aUsers[key][2] = aUsers[key][2] + totalSize
else
aUsers[key] = {nDownloads, totalSize}
end
end
function printTable(t)
local str = ""
-- How to sort 't' so that it prints in v[2] descending order?
for k,v in pairs(t) do
str = str .. k .. ", " .. v[1] .. ", " .. v[2] .. "\n"
end
return str
end
...
任何想法我怎么能这样做?
答案 0 :(得分:2)
您可以将密钥放入单独的表中,然后使用您需要的条件对该表进行排序:
local t = {
a = {1,2},
b = {2,3},
c = {4,1},
d = {9,9},
}
local keys = {}
for k in pairs(t) do table.insert(keys, k) end
table.sort(keys, function(a, b) return t[a][2] > t[b][2] end)
for _, k in ipairs(keys) do print(k, t[k][1], t[k][2]) end
将打印:
d 9 9
b 2 3
a 1 2
c 4 1