Question

我正在为我的用户实施一项关注功能。为此，我按照micheal hartl教程的指示_{link needed}，但是我收到了这个错误：

undefined method id' for nil:NilClass  <% if current_user.following?(@user) %>

这是我的用户模型

  has_many :relationships, foreign_key: "follower_id", dependent: :destroy
  has_many :followed_users, through: :relationships, source: :followed

  has_many :reverse_relationships, foreign_key: "followed_id",
                                   class_name:  "Relationship",
                                   dependent:   :destroy
  has_many :followers, through: :reverse_relationships, source: :follower


  def following?(user)
    relationships.find_by(followed_id: user.id)
  end

  def follow!(user)
    relationships.create!(followed_id: user.id)
  end

  def unfollow!(user)
    relationships.find_by(followed_id: user.id).destroy
  end

这是我的关系模式

class Relationship < ActiveRecord::Base
    belongs_to :follower, class_name: "User"
    belongs_to :followed, class_name: "User"

    validates :follower_id, presence: true
    validates :followed_id, presence: true
end

这是我的观点

<% if current_user.id && current_user.id != user.id %>
  <div id="follow_form">
     <% if current_user.following?(@user) %>
        <%= form_for(current_user.relationships.find_by(followed_id: @user.id),
                                                html: { method: :delete }) do |f| %>
          <%= f.submit "Unfollow", class:"unfollow-button"  %>
        <% end %>
    <% else %>
        <%= form_for(current_user.relationships.build(followed_id: @user.id)) do |f| %>
            <div><%= f.hidden_field :followed_id %></div>
            <%= f.submit "Follow", class:"follow-button"  %>
    <% end %>
<% end %>

这是用户控制器

def show
    @user= User.find_by_slug(params[:id])
    if @user
      @posts= Post.all
      render action: :show
    else
      render file: 'public/404', status: 404, formats: [:html]
    end
  end

  def index
    @users = (current_user.blank? ? User.all : User.find(:all, :conditions => ["id != ?", current_user.id]))
  end

Answer 1

这意味着@user为零。通过执行

确保@user对象不为空

= debug @user

那应打印有关@user对象的所有详细信息。

关注用户关系

1 个答案: