我在从SP中的日期字段中检索时间时遇到问题。如果我运行查询:
select TO_CHAR(HOR_HST_ATN,'YYYY/MM/DD HH24:MI:SS') AS HOR_HST_ATN FROM AAM0_DT_RSTCN ;
它返回日期和时间。
但在SP中,代码:
SELECT FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN,
TO_DATE(HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS') as HOR_DSD_ATN,
TO_DATE(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS') as HOR_HST_ATN
只返回日期,但时间是00:00
如果我在SP中使用TO_CHAR尝试选择:
SELECT FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN,
TO_CHAR(HOR_DSD_ATN ,'YYYY/MM/DD HH24:MI:SS') as HOR_DSD_ATN,
TO_CHAR(HOR_HST_ATN,'YYYY/MM/DD HH24:MI:SS') as HOR_HST_ATN
我收到错误: SQLCODE:-6502 SQLERRM:ORA-06502:PL / SQL:错误...
任何线索?顺便说一下,我必须使用SP来检索这个值。
更新:列是类型日期。这是完整的SP:
FUNCTION FN_AAM_EV_RSTCN (
I_NUM_CONTRATO IN AAM0_DT_RSTCN.NUM_CONTRATO%TYPE,
I_COD_PFL IN AAM0_DT_RSTCN.COD_PFL%TYPE,
I_COD_APL_PFM IN AAM0_DT_RSTCN.COD_APL_PFM%TYPE,
I_COD_PTO IN AAM0_DT_RSTCN.COD_PTO%TYPE,
I_COD_FNC IN AAM0_DT_RSTCN.COD_FNC%TYPE
) RETURN BOOLEAN
AS
T_FEC_DSD_ATN AAM0_DT_RSTCN.FEC_DSD_ATN%TYPE;
T_HOR_DSD_ATN AAM0_DT_RSTCN.HOR_DSD_ATN%TYPE;
T_FEC_HST_ATN AAM0_DT_RSTCN.FEC_HST_ATN%TYPE;
T_HOR_HST_ATN AAM0_DT_RSTCN.HOR_HST_ATN%TYPE;
T_NOM_SEM_DSD_ATN AAM0_DT_RSTCN.NOM_SEM_DSD_ATN%TYPE;
T_NOM_SEM_HST_ATN AAM0_DT_RSTCN.NOM_SEM_HST_ATN%TYPE;
O_RESULTSET2 REST_REFCUR;
BEGIN
OPEN O_RESULTSET2 FOR
SELECT FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN,
TO_CHAR(HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS') as HOR_DSD_ATN,
TO_CHAR(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS') as HOR_HST_ATN
FROM AAM0_DT_RSTCN
WHERE ROWNUM <=1
AND NUM_CONTRATO = NVL ( I_NUM_CONTRATO, NUM_CONTRATO )
AND COD_PFL = NVL ( I_COD_PFL, COD_PFL )
AND COD_APL_PFM = NVL ( I_COD_APL_PFM, COD_APL_PFM )
AND COD_PTO = NVL ( I_COD_PTO, COD_PTO )
AND COD_FNC = NVL ( I_COD_FNC, COD_FNC )
AND FLG_RCS = 'D'
AND COD_TPO_CDC = 'PC'
;
FETCH O_RESULTSET2 INTO T_FEC_DSD_ATN, T_FEC_HST_ATN, T_NOM_SEM_DSD_ATN, T_NOM_SEM_HST_ATN, T_HOR_DSD_ATN, T_HOR_HST_ATN ;
IF (O_RESULTSET2%NOTFOUND) THEN
RETURN TRUE;
ELSE
dbms_output.put_line('EVALUO RESTRICCIONES: T_FEC_DSD_ATN ' || T_FEC_DSD_ATN || ' T_FEC_HST_ATN : ' || T_FEC_HST_ATN || ' T_NOM_SEM_DSD_ATN: ' ||
T_NOM_SEM_DSD_ATN || ' T_NOM_SEM_HST_ATN: ' || T_NOM_SEM_HST_ATN || ' T_HOR_DSD_ATN: ' || TO_CHAR(T_HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS') ||
' T_HOR_HST_ATN: ' || TO_CHAR(T_HOR_HST_ATN ,'DD/MM/YYYY HH24:MI:SS') );
IF (NOT((T_FEC_DSD_ATN IS NULL) and (T_FEC_HST_ATN IS NULL)) ) THEN
IF ( NOT ((T_FEC_DSD_ATN <= SYSDATE) AND (T_FEC_HST_ATN >= SYSDATE ))) THEN
RETURN FALSE;
END IF ;
END IF ;
RETURN TRUE;
END IF ;
EXCEPTION
WHEN NO_DATA_FOUND THEN
RETURN TRUE;
WHEN OTHERS THEN
IF O_RESULTSET2%ISOPEN THEN
CLOSE O_RESULTSET2;
END IF;
DBMS_OUTPUT.PUT_LINE('ERROR en FN_AAM_EV_RSTCN : ');
DBMS_OUTPUT.PUT_LINE(' SQLCODE: ' || SQLCODE );
DBMS_OUTPUT.PUT_LINE(' SQLERRM: ' || SQLERRM );
ROLLBACK;
END FN_AAM_EV_RSTCN;
答案 0 :(得分:3)
您的问题在于以下代码:
...
T_HOR_DSD_ATN AAM0_DT_RSTCN.HOR_DSD_ATN%TYPE;
T_HOR_HST_ATN AAM0_DT_RSTCN.HOR_HST_ATN%TYPE;
...
SELECT FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN,
TO_CHAR(HOR_DSD_ATN ,'DD/MM/YYYY HH24:MI:SS') as HOR_DSD_ATN,
TO_CHAR(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS') as HOR_HST_ATN
FROM AAM0_DT_RSTCN
...
FETCH O_RESULTSET2 INTO T_FEC_DSD_ATN, T_FEC_HST_ATN, T_NOM_SEM_DSD_ATN,
T_NOM_SEM_HST_ATN, T_HOR_DSD_ATN, T_HOR_HST_ATN ;
由于HOR_DSD_ATN
和HOR_HST_ATN
列具有DATE数据类型,因此您的本地变量(T_HOR_DSD_ATN
和T_HOR_HST_ATN
)也是DATE。但是,在SELECT中,您将这些日期转换为具有TO_CHAR函数的字符串。因此,你的fetch实际上是这样做的(我在这里编写了一些日期):
T_HOR_DSD_ATN := '03/02/2010 09:33:30';
T_HOR_HST_ATN := '01/01/2010 12:30:00';
由于您要将字符串分配给日期变量,因此Oracle必须执行隐式TO_DATE - 因此它使用会话的NLS_DATE_FORMAT来转换它们,这可能只是获取日期部分(例如DD/MM/YYYY
)并且丢失了时间价值。
要修复它,只需从SELECT语句中删除TO_CHAR() - 这样就可以将日期+时间值未修改为局部变量。
答案 1 :(得分:2)
由于TO_DATE
函数将VARCHAR作为参数,因此不会在DATE字段上使用此函数。如果要从DATE字段中检索日期和时间,则只需选择不带函数的字段:
SELECT FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN, NOM_SEM_HST_ATN,
HOR_DSD_ATN, HOR_HST_ATN
...
问题在于您将TO_CHAR(HOR_DSD_ATN, 'DD/MM/YYYY HH24:MI:SS')
提取到DATE字段中。隐式转换会截断您的日期。在DATE变量上使用to_char
,在CHAR变量上使用to_date
。
我的建议:
FUNCTION FN_AAM_EV_RSTCN(I_NUM_CONTRATO IN AAM0_DT_RSTCN.NUM_CONTRATO%TYPE,
I_COD_PFL IN AAM0_DT_RSTCN.COD_PFL%TYPE,
I_COD_APL_PFM IN AAM0_DT_RSTCN.COD_APL_PFM%TYPE,
I_COD_PTO IN AAM0_DT_RSTCN.COD_PTO%TYPE,
I_COD_FNC IN AAM0_DT_RSTCN.COD_FNC%TYPE)
RETURN BOOLEAN AS
BEGIN
FOR cc IN (SELECT FEC_DSD_ATN, FEC_HST_ATN, NOM_SEM_DSD_ATN,
NOM_SEM_HST_ATN, HOR_DSD_ATN, HOR_HST_ATN
FROM AAM0_DT_RSTCN
WHERE ROWNUM <= 1
AND NUM_CONTRATO = NVL(I_NUM_CONTRATO, NUM_CONTRATO)
AND COD_PFL = NVL(I_COD_PFL, COD_PFL)
AND COD_APL_PFM = NVL(I_COD_APL_PFM, COD_APL_PFM)
AND COD_PTO = NVL(I_COD_PTO, COD_PTO)
AND COD_FNC = NVL(I_COD_FNC, COD_FNC)
AND FLG_RCS = 'D'
AND COD_TPO_CDC = 'PC') LOOP
dbms_output.put_line(' T_HOR_DSD_ATN: ' ||
TO_CHAR(cc.HOR_DSD_ATN, 'DD/MM/YYYY HH24:MI:SS') ||
' T_HOR_HST_ATN: ' ||
TO_CHAR(cc.HOR_HST_ATN, 'DD/MM/YYYY HH24:MI:SS'));
-- your logic with return boolean
END LOOP;
-- no rows found
RETURN TRUE;
EXCEPTION
WHEN OTHERS THEN
DBMS_OUTPUT.PUT_LINE('ERROR en FN_AAM_EV_RSTCN : ');
DBMS_OUTPUT.PUT_LINE(' SQLCODE: ' || SQLCODE);
DBMS_OUTPUT.PUT_LINE(' SQLERRM: ' || SQLERRM);
RAISE;
END FN_AAM_EV_RSTCN;
答案 2 :(得分:0)
如果HOR_HST_ATN是日期列,则TO_DATE(HOR_HST_ATN,'DD/MM/YYYY HH24:MI:SS')
必须是拼写错误。你可能意味着TO_CHAR()。
答案 3 :(得分:0)
如果列由没有时间元素的日期填充,则Oracle将默认时间设置为午夜...
SQL> create table t23 (d date)
2 /
Table created.
SQL> insert into t23 values (sysdate)
2 /
1 row created.
SQL> insert into t23 values (to_date('03-FEB-2010', 'DD-MON-YYYY'))
2 /
1 row created.
SQL> select to_char(d, 'DD/MM/YYYY HH24:MI:SS') as datetime from t23
2 /
DATETIME
-------------------
02/02/2010 17:59:51
03/02/2010 00:00:00
SQL>