Question

我是Oracle SQL的新手。我试图显示门票名称，关闭和打开门票的数量以及日期。但我无法得到正确的查询。

期望的输出：

01/20/2014, User management, 20, 15

查询：

SELECT 'Data'
||','||TO_CHAR(D.DTIME_DAY,'MM/dd/yyyy')
||','||q.name -- as ticket
||','||NVL(o.CNT_OPENED,0) --as cnt_opened
||','||NVL(c.CNT_CLOSED,0) --as cnt_closed
FROM OWNER_DWH.DC_DATE d
LEFT JOIN (
SELECT q.name, count(q.name), TRUNC(t.CREATE_TIME) as report_date, count(*) as  cnt_opened
FROM APP_ACCOUNT.OTRS_TICKET t
left join app_account.otrs_queue q
ON q.ID = t.QUEUE_ID
WHERE t.CREATE_TIME BETWEEN SYSDATE -7 AND SYSDATE -1
and t.queue_id not in (63, 61, 69, 59, 58, 60, 56, 64, 65, 23, 67, 68, 57)
GROUP BY q.name, TRUNC(t.CREATE_TIME)
) o ON d.DTIME_DAY=o.REPORT_DATE
LEFT JOIN (
SELECT q.name, count(q.name), TRUNC(t.CLOSE_TIME) as report_date,count(*) AS cnt_closed
FROM APP_ACCOUNT.OTRS_TICKET t
left join app_account.otrs_queue q
ON q.ID = t.QUEUE_ID
WHERE t.CLOSE_TIME BETWEEN SYSDATE -7 AND SYSDATE -1
and t.queue_id not in (63, 61, 69, 59, 58, 60, 56, 64, 65, 23, 67, 68, 57)
GROUP BY q.name, TRUNC(t.CLOSE_TIME)
) c ON D.DTIME_DAY=c.REPORT_DATE
WHERE d.DTIME_DAY BETWEEN SYSDATE -7 AND TRUNC(SYSDATE) -1
AND TRUNC(d.DTIME_DAY)= d.DTIME_DAY
ORDER BY D.DTIME_DAY;

如果我想分组数据？

示例：在一栏中，假设我有：

 E-mail management
 E-mail management::Add user e-mail
 E-mail management::Add new Outlook distribution list
 E-mail management::Add new Outlook shared mailbox
 E-mail management::Add new SA e-mail (Zimbra account)
 POS::POS issue - need paper
 POS::POS issue - internet connection problems

具有电子邮件管理功能的所有名称将分组为电子邮件管理，所有具有POS的名称将分组为POS。

欲望输出：

  02/10/2014, E-mail, 4
  02/10/2014, POS, 2

怎么做？

请帮帮我。提前谢谢。

Answer 1

你可以这样做：

group by (case when col like 'E-mail management:%' then 'E-mail management'
               when col like 'pos:%' then 'pos'
               else col
           end)

按冒号前的部分聚合：

group by substr(col, 1, instr(col, ':') - 1)

或

group by (case when col like '%:%' then substr(col, 1, instr(col, ':') - 1)
               else col
          end)

当然，您必须修复select子句以与group by子句兼容。

编辑：

要计算组中的数字，您可以执行以下操作：

select (case when col like '%:%' then substr(col, 1, instr(col, ':') - 1)
             else col
        end), count(*)
from table t
group by (case when col like '%:%' then substr(col, 1, instr(col, ':') - 1)
               else col
          end)

如何在一列内分组数据？

1 个答案: