Question

我需要一些帮助.....我打算在android中创建一个火焰应用程序......我搞砸了编码。任何人都可以帮助我。我正在尝试打印不常见的字母数量。这是编码。我需要找到一些方法来查找常见字符的数量。

`package com.rajzflames;

//import com.kct.health_maintainer.Chk;

import android.os.Bundle;
import android.app.Activity;
import android.text.Editable;
import android.view.Menu;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;

public class MainActivity extends Activity 
{
int i = 0;
int j = 0, k;
String p;
Editable st1;
Editable st2;
// final int i=0;
// final int j=0;
// String,p;

@Override
protected void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity1);

    final TextView t = (TextView) findViewById(R.id.tv1);
    Button bt1 = (Button) findViewById(R.id.bt1);
    final EditText e1 = (EditText) findViewById(R.id.et1);
    EditText e2 = (EditText) findViewById(R.id.et2);

    st1 = e1.getText();
    st2 = e2.getText();

    bt1.setOnClickListener(new View.OnClickListener() 
    {
        @Override
        public void onClick(View v) 
        {
            while (i < st1.length()) 
            {
                while (j < st2.length()) 
                {
                    if (st1.charAt(i) == st2.charAt(j)) 
                    {
                        st1.delete(i, i);
                        st2.delete(j, j);
                        i++;
                        // j++;
                    }
                    j++;
                }
                i++;
            }
            k = st1.length() + st2.length();
            p = Integer.toString(k);
            Toast.makeText(MainActivity.this, p, Toast.LENGTH_LONG).show();
        }
    });
}
}

Answer 1

您可以通过以下方法找到常用字符数。我已将p更改为int

bt1.setOnClickListener(new View.OnClickListener()
{
    @Override
    public void onClick(View v)
    {
        ArrayList<Character> charArray1 = new ArrayList<Character>();
        ArrayList<Character> charArray2 = new ArrayList<Character>();

        for (char character : st1.toString().toCharArray())
        {
            charArray1.add(character);
        }

        for (char character : st2.toString().toCharArray())
        {
            charArray2.add(character);
        }

        for (Character character : charArray2)
        {
            if (charArray1.contains(character))
                p++;
        }

        Toast.makeText(PlayActivity.this, "" + p, Toast.LENGTH_LONG).show();

    }

});

android代码出错

1 个答案: