Question

我正在尝试通过以下方案。但是遇到了这个编译时错误。

The type 'DerivedDefinition' cannot be used as type parameter 'T' in the generic type or method 'BaseInstance<T>'. There is no boxing conversion or type parameter conversion from 'DerivedDefinition' to 'BaseDefinition'.

原因是什么？如何解决？

这与上一个问题https://stackoverflow.com/questions/21718509/supporting-generic-and-non-generic-implementation

有关

更新：这是基于下面提供的答案的正确工作代码

public abstract class BaseDefinition 
{
    public virtual void Print() { Console.WriteLine("base definition"); }
}
public class DerivedDefinition : BaseDefinition 
{
    public override void Print() { Console.WriteLine("derived definition"); }
}


public abstract class BaseInstance
{
    protected BaseDefinition definition;
    public BaseDefinition Definition { get { return definition; } }
}

public abstract class BaseInstance<T> : BaseInstance where T : BaseDefinition
{
    //public T DefinitionExact { get { return (T)definition; } }
}

public class DerivedInstance : BaseInstance<DerivedDefinition>
{
    public DerivedInstance() 
    {
        definition = new DerivedDefinition();
    }
}


class TestClass
{
    static void Main(string[] args)
    {
        BaseInstance baseInstance = new DerivedInstance();
        baseInstance.Definition.Print();
        //baseInstance.DefinitionExact.Print();

        DerivedInstance derivedInstance = new DerivedInstance();
        derivedInstance.Definition.Print();
    }
}

以下代码非常错误......

public abstract class BaseDefinition 
{
    public virtual string Print() { Console.WriteLine("base definition"); }
}
public class DerivedDefinition : BaseDefinition 
{
    public override string Print() { Console.WriteLine("derived definition"); }
}


public abstract class BaseInstance
{
    private BaseDefinition definition;
    protected BaseDefinition Definition { get { return definition; } }
}

public abstract class BaseInstance<T> : BaseInstance where T : BaseDefinition
{
    protected T DefinitionExact { get { return (T)definition; } }
}

public class DerivedInstance<DerivedDefinition> : BaseInstance<DerivedDefinition>
{
    public DerivedInstance() 
    {
        definition = new DerivedDefinition();
    }
}


class TestClass
{
    static void Main(string[] args)
    {
        BaseInstance baseInstance = new DerivedInstance<DerivedDefinition>();
        baseInstance.Definition.Print();
        baseInstance.DefinitionExact.Print();

    }
}

Answer 1

您的通用设置存在问题：

    public class DerivedInstance<DerivedDefinition> : BaseInstance<DerivedDefinition>
{
    public DerivedInstance() 
    {
        definition = new DerivedDefinition();
    }
}

当您声明一个通用类时，您将名称放在＆lt;＆gt;中这将是您的类内部处理的类型。您想要替换，因此您的代码如下所示：

    public class DerivedInstance<T> : BaseInstance<T>
{
    public DerivedInstance() 
    {
        definition = new DerivedDefinition();
    }
}

Answer 2

要解决编译器错误，您需要约束派生类中的type参数，以使其满足基类中的约束：

public class DerivedInstance<DerivedDefinition> : BaseInstance<DerivedDefinition>
    where DerivedDefinition : BaseDefinition
{
    public DerivedInstance() 
    {
        definition = new DerivedDefinition();
    }
}

但是，由于你的类型参数的名称与你的一个类名相同，我怀疑你实际上是想这样做：

public class DerivedInstance : BaseInstance<DerivedDefinition>
{
    public DerivedInstance() 
    {
        definition = new DerivedDefinition();
    }
}

也就是说，DerivedInstance类可能根本不是通用的，而是你打算提供DerivedDefinition作为基类类型参数的参数。

没有从派生到基类的拳击转换

2 个答案: