Question

我有如下建议.php如下。此表单操作调用suggestion_add.php将建议记录添加到db中。如果表单提交我想显示成功消息。现在，它不显示任何消息，用户保持单击提交按钮并插入重复记录。

谢谢，亚历

Suggestion.php

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="utf-8">
  <meta http-equiv="X-UA-Compatible" content="IE=edge">
  <meta name="viewport" content="width=device-width, initial-scale=1.0">
  <meta name="description" content="">
  <meta name="author" content="">
  <link rel="shortcut icon" href="images/favicon.png">
  <title></title>
  <link href="css/bootstrap.css" rel="stylesheet">
  <link href="css/style.css" rel="stylesheet">
  <script src="js/jquery.form.js"></script>
</head>
<body>
  <div class="navbar navbar-inverse navbar-fixed-top" role="navigation">
    <div class="container">
      <div class="navbar-header">
        <a class="navbar-brand" href="#">SUGGEST VIDEO</a>
      </div>
    </div>
  </div>
  <div class="container">
    <form class="suggestion" role="form" method="POST" action="suggestion_add.php">
      <div class="form-group"><label name="warnning" id="urlwarnning">Currently we only support YouTube as well as Vimeo videos</label></div>
      <div class="form-group"><input name="url" id="url" type="text" class="form-control" placeholder="URL" required></div>
      <div class="form-group"><input name="title" id="title" type="text" class="form-control" placeholder="Title" required></div>
      <div class="form-group"><textarea id="desc" name="desc" class="form-control" rows="5" placeholder="Description.." required></textarea></div>
      <div class="form-group"><input name="name" id="name" type="text" class="form-control" placeholder="Name" required></div>
      <div class="form-group"><input name="email" id="email" type="text" class="form-control" placeholder="Email ID" required></div>
      <button class="btn btn-lg btn-primary btn-block" type="submit">SUBMIT</button>
    </form>


  </div> <!-- /container -->
  <script src="js/jquery.js"></script>
  <script src="js/index.js"></script>
</body>
</html>

Suggestion_add.php

<?php
include("config.php");
$con=mysql_connect($db_host,$db_uname,$db_pwd,$db_name);
mysql_select_db($db_name);
$src=$_POST['src'];
$name=$_POST['name'];
$email=$_POST['email'];
$title=$_POST['title'];
$desc=$_POST['desc'];
$vid=$_POST['vid'];
$query="INSERT INTO `suggestion` (`id`,`src`,`vid`,`title`,`desc`,`name`,`email`)VALUES (NULL,'$src','$vid','$title','$desc','$name','$email');";
$result=mysql_query($query);
?>

表单提交后显示成功消息

0 个答案: