Question

我很难理解为什么这个表格不起作用。我收到了成功的消息，但没有任何内容被发送到我的收件箱，我也检查了我的垃圾邮件。即使等了几分钟，仍然没有任何表现。我对ajax或php并不熟悉，所以我可能对这部分做错了。

我正在使用两个插件，http://malsup.github.io/jquery.form.js和http://jquery.bassistance.de/validate/jquery.validate.js。

html（“corner”div仅用于造型目的）

       <form action="contact-form.php" method="post" autocomplete="off" id="contact">

            <div class="corner"></div>
            <input type="text" required name="name" placeholder="Name" class="name">

            <div class="corner"></div>
            <input type="email" required name="email" placeholder="Email" class="email">

            <div class="corner"></div>
            <div id="contact-check">You sure 'bout that?</div>
            <input type="text" required name="check" placeholder="Quick! What's 2 + 2 ?" class="check">

            <div class="corner"></div>
            <textarea name="message" rows="25" cols="50" placeholder="Drop me a line!"></textarea>

            <input type="submit" name="submit" value="send" class="send" />
        </form>

jquery（使用ajax）

var contactForm = $('form#contact')
    inputCheck = $('input.check')
    contactCheck = $('div#contact-check');

// Check if answered math question correctly
inputCheck.keyup(function(){
    if($(this).val() == 4){
        contactCheck.fadeOut();
    } else {
        contactCheck.fadeIn();
    }
});

// Validate input from contact form
$('form#contact').validate({
  submitHandler: function(form) {
    $(form).ajaxSubmit({
      clearForm: true,
      success: function(){
        // if it's good, do this
        contactCheck.fadeOut();
        alert("Thanks, I'll get back to you soon!");
      }
    });
    return false;
  },
  invalidHandler: function(form) {
    // if it's bad, do this
    alert('Oops, something went wrong.');
  }
});

最后是php

$name = $_POST['name'];
$email = filter_var( $_POST['email'],FILTER_VALIDATE_EMAIL );
$message = $_POST['message'];
$from = 'From: MessageForAnita'; 
$to = 'myemail@gmail.com'; 
$subject = 'Hello';
$check = $_POST['check'];

$body = " From: $name\n E-Mail: $email\n Message:\n $message";


if ($_POST['submit'] && $check == '4') {                 
    if (mail ($to, $subject, $body, $from)) { 
        echo 'Your message was sent!';
    } else { 
        echo 'Something went wrong, go back and try again!'; 
    } 
}

Answer 1

您需要检查您发送的标头，并确保它们格式正确。

这未经过测试，但可以让您了解应该做些什么：

$name       = $_POST['name'];
$message    = $_POST['message'];
$email      = filter_var( $_POST['email'],FILTER_VALIDATE_EMAIL );

$to         = 'myemail@gmail.com'; 
$subject    = 'Hello MessageForAnita';
$body       = "From: $name\n E-Mail: $email\n Message:\n $message";

// In case any of our lines are larger than 70 characters, we should use wordwrap()
$body       = wordwrap($body, 70, "\r\n");

$headers    = "From: $email" . "\r\n"; 

if ($_POST['submit'] && $check == '4') {                 
    if (mail ($to, $subject, $body, $headers)) { 
        echo 'Your message was sent!';
    } else { 
        echo 'Something went wrong, go back and try again!'; 
    } 
}

PHP mail function

Answer 2

我编辑了php到

$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];

$to = "myemail@gmail.com"; 
$subject = 'You have a message sent from your site';

$check = $_POST['check'];

$body = "From: $name\n E-Mail: $email\n Message:\n $message";

mail($to, $subject, $body);

我很幸运收到了新邮件的通知。但是$ name，$ email和$ message没有值，所以我只收到一封“From：E-Mail：Message：”的电子邮件，以解决下一个问题。感谢所有的评论。还需要使这种形式更安全。

更新：我终于弄明白了。几天前我改变了我的.htaccess文件，忘记在链接到联系表单时取出.php扩展名。这简直太简单了吗？

我无法弄清楚为什么这个联系表格不起作用

2 个答案: