这里的目标是从日志文件中获取文本,由返回分隔的纯文本,每行由不同数量的空格分隔。
将它变成多维是很容易的,摆脱空白不是。我想有很多混乱的方法可以解决这个问题,但这不是array_filter()的原因之一吗?
$alarms = array(
"1530 1545 Place_4 Fault_1",
"1617 1622 Place_1 Fault_2",
"1634 1640 Place_2 Fault_1"
);
foreach ($alarms as $data) {
$subArr = explode(" ", $data);
array_filter($subArr);
print_r($subArr);
echo "<br /><br />";
}
输出:
Array ( [0] => 1530 [1] => [2] => [3] => [4] => [5] => 1545 [6] => [7] => [8] => [9] => [10] => Place_4 [11] => [12] => [13] => [14] => [15] => Fault_1 )
Array ( [0] => 1617 [1] => [2] => [3] => [4] => [5] => 1622 [6] => [7] => [8] => [9] => [10] => Place_1 [11] => [12] => [13] => [14] => [15] => Fault_2 )
Array ( [0] => 1634 [1] => [2] => [3] => [4] => [5] => 1640 [6] => [7] => [8] => [9] => [10] => Place_2 [11] => [12] => [13] => [14] => [15] => Fault_1 )
希望它成为:
数组([0] =&gt; 1530 [1] =&gt; 1545 [2] =&gt; Place_4 [3] =&gt; Fault_1)
数组([0] =&gt; 1617 [1] =&gt; 1622 [2] =&gt; Place_1 [3] =&gt; Fault_2)
数组([0] =&gt; 1634 [1] =&gt; 1640 [2] =&gt; Place_2 [3] =&gt; Fault_1)
不确定是什么问题......
干杯。
答案 0 :(得分:9)
答案 1 :(得分:0)
而不是explode(" ",$something)
,试试这个:
$parts = preg_split("/ +/",$something);
这将分成可变数量的空格。
答案 2 :(得分:0)
更新代码
$alarms = array(
"1530 1545 Place_4 Fault_1",
"1617 1622 Place_1 Fault_2",
"1634 1640 Place_2 Fault_1"
);
foreach ($alarms as $data) {
$subArr = explode(" ", $data);
$subArr = array_filter($subArr);
print_r($subArr);
echo "<br /><br />";
}
答案 3 :(得分:0)
$array = array(
0 => '0130085779',
1 => '0130085779',
2 => '0130181129',
3 => '0130181296',
4 => '0130181448',
5 => '0130214980'
);
$array = array_filter($array);
我使用了此功能,但是不起作用。