Question

这是我在数据库解决方案中的代码

public HashMap<String, String> getBookTheme(){

    HashMap<String, String> hm = new HashMap<String, String>();
    Cursor cursor = db.rawQuery("SELECT title, filepath FROM " + 
                BooksDBHelper.TABLE_BOOK + " INNER JOIN" + BooksDBHelper.TABLE_THEME +
                " ON " + BooksDBHelper.TABLE_BOOK + " . " + 
                BooksDBHelper.KEY_BOK_ID + " = " + BooksDBHelper.TABLE_THEME + 
                " . " + BooksDBHelper.KEY_BOK_ID, null);
    cursor.moveToLast();
    if(cursor.getCount() != 0){
        do{

            hm.put("title", cursor.getString(cursor.getColumnIndex(BooksDBHelper.KEY_TITLE)));
            hm.put("Theme", cursor.getString(cursor.getColumnIndex(BooksDBHelper.KEY_fILEPATH)));

        }while(cursor.moveToNext());

    }

    return hm;

}

这是我的logcat错误

android.database.sqlite.SQLiteException: near "ON": syntax error (code 1): , while compiling: SELECT title, filepath FROM books INNER JOINtheme ON books . bookID = theme . bookID WHERE bookID != ?

请检查并告诉我一个收集语法。谢谢观看：））））

Answer 1

JOIN和表1名称之间没有空格（“”）。表名和表之间有额外的空间。列名

将其更改为：

SELECT title, filepath FROM books INNER JOIN theme ON books.bookID = theme.bookID WHERE bookID != ?

我认为你没事。

希望这有帮助。

语法错误sqlite内连接

1 个答案: