Question

我正在尝试使用本教程使用MySQL数据库中的数据填充Select2下拉列表：http://www.southcoastweb.co.uk/jquery-select2-ajax-tutorial/

这是我正在使用的PHP脚本（从原始版本略微修改）：

<?php
    // setup databse connection
    require("../scripts/connect.php");

    // i have set the limit to 40 to speed up results
    $result = $db->prepare("SELECT id,model FROM vehicles WHERE model LIKE :term ORDER BY model ASC LIMIT 0,40");

    // bind the value for security with the wildcard % attached.
    $result->bindvalue(':term','%'.$_GET["q"].'%',PDO::PARAM_STR);
    $result->execute();

    // make sure there are some results else a null query will be returned
    if($result->rowcount() != 0) {
        while($row = $result->fetch(PDO::FETCH_ASSOC)){
            $answer[] = array("id"=>$row['id'],"text"=>$row['id']." - ".$row['model']);
            // the text I want to show is in the form of option id - option
        }
    } else {
    // 0 results send a message back to say so.
        $answer[] = array("id"=>"0","text"=>"No Results Found..");
    }

    // finally encode the answer to json and send back the result.
    echo json_encode($answer);

这是数据库布局：

CREATE TABLE `vehicles` (
    `id` int(11) NOT NULL AUTO_INCREMENT,
    `carline` varchar(125) NOT NULL,
    `model` varchar(255) NOT NULL,
    `year` varchar(12) NOT NULL,
    `engine` varchar(255) NOT NULL,
    `airconditioning` enum('Yes','No') NOT NULL,
    `transmission` enum('Automatic','Manual') NOT NULL,
    `drive` enum('2WD','4WD') NOT NULL,
    `designation` enum('Passenger','Commercial') NOT NULL,
    PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=14 ;

这是我收到的错误：

[08-Feb-2014 18:28:06太平洋/奥克兰] PHP注意：未定义变量：db在/Users/.../app/scripts/serviceplan_values.php上 6 [08-Feb-2014 18:28:06太平洋/奥克兰] PHP致命错误：致电a 成员函数prepare（）在非对象中第6行/Users/.../app/scripts/serviceplan_values.php

任何想法？

Answer 1

错误最有可能发生在connect.php，您需要设置$db变量。

调用成员函数ERROR PHP

1 个答案: