我有一张名为门票的桌子。 Tickets表有4列:user_id
,ticket_id
,subject
,message
。我想循环登录用户的ticket_id和主题。我想用foreach回应它,但我不能让它工作。这就是我所拥有的:
查询:
$showTheTickets = array();
$user_id = $_SESSION['user_id'];
$getTickets = mysqli_query($mysqli,"SELECT * FROM tickets WHERE user_id = '$user_id'") OR die (mysqli_error($mysqli));
while($row = mysqli_fetch_assoc($getTickets)){
$showTicketID = $row['ticket_id'];
$showTicketSubject = $row['subject'];
}
页面中的代码:
<?php foreach ($showTheTickets as $showTheTickets): ?>
<div class="preview">
<?php echo $showTicketID ?>
<?php echo $showTicketSubject ?>
</div>
<?php endforeach; ?>
有人愿意帮助我吗?感谢。
答案 0 :(得分:0)
您正在覆盖从查询中获得的值,并且$showTheTickets
数组仍为空。
您可能需要以下内容:
$showTheTickets = array();
while($row = mysqli_fetch_assoc($getTickets)){
$showTheTickets[$row['ticket_id']] = $row['subject'];
}
和
<?php foreach ($showTheTickets as $id => $subject): ?>
<div class="preview">
<?php echo $id; ?>
<?php echo $subject; ?>
</div>
<?php endforeach; ?>
答案 1 :(得分:0)
为什么不简单
while($row = mysqli_fetch_assoc($getTickets)){
?><div class="preview"><?
echo $row['ticket_id'];
echo $row['subject'];
?></div><?
}
答案 2 :(得分:0)
你必须将$ showTicketID和$ showTicketSubject保存在一个数组中(可以是相同的数组或2个数组),然后在视图中显示数组,如下所示:
while($row = mysqli_fetch_assoc($getTickets)){
$array[$row['ticket_id']] = $row['subject'];
}
和视图:
<?php foreach ($showTheTickets as $ticketid => $ticketsubject): ?>
<div class="preview">
<?php echo $ticketid ?>
<?php echo $ticketsubject ?>
</div>
<?php endforeach; ?>
答案 3 :(得分:0)
试试这个:
$showTheTickets = array();
$user_id = $_SESSION['user_id'];
$getTickets = mysqli_query($mysqli,"SELECT * FROM tickets WHERE user_id = $user_id") OR die (mysqli_error($mysqli));
while($row = mysqli_fetch_array($getTickets)){
$row = array( 'ticket_id' => $row['ticket_id'], 'subject' => $row['subject'] );
$showTheTickets[] = $row;
}
然后:
<?php foreach ($showTheTickets as $stt): ?>
<div class="preview">
<?php echo $stt['ticket_id'] ?>
<?php echo $stt['subject'] ?>
</div>
<?php endforeach; ?>
希望它有所帮助...