Question

我有一项任务是从一段文字中删除一部分字符串。这个概念如下。

1）应删除文本段落中括号“（”和“）”中字符串的部分。

2）然后，如果左括号距原始字符串的开头不超过30个字符，则不删除。

实施例

$sample_string = 'Pete Fountain (born Pierre Dewey LaFontaine, Jr., July 3, 1930), is an American, New Orleans based clarinetist. According to a Belgian radio program ("La troisieme oreille", produced by Marc Danval), his name was originally Pierre de la Fontaine.';

$output_string = 'Pete Fountain, is an American, New Orleans based clarinetist. According to a Belgian radio program ("La troisieme oreille", produced by Marc Danval), his name was originally Pierre de la Fontaine.'

注意：

虽然右括号“）”超出了字符串的第30个字符，但仍然必须删除字符串的部分。

括号内的许多文本都可以以第30个字符显示。

Answer 1

看起来这可能是一项任务，所以我不想直截了当地回答......但我会给你一些指示。

如果你看一下这里：http://uk3.php.net/manual/en/function.stripos.php你会找到一个函数，它允许你在一个字符串中找到一个字符的出现。

此功能：http://uk3.php.net/substr将允许您从字符串中获取内容。

而且：http://uk1.php.net/strlen会让你获得字符串长度。

阅读PHP文档，玩游戏，看看你能想出什么。

Answer 2

但是我同意Richard Simpson的观点，我想我们只需要给你一个有效的例子。这样你下次就可以自己做（或至少学点东西）。

$sample_string = 'Pete Fountain (born Pierre Dewey LaFontaine, Jr., July 3, 1930), is an American, New Orleans based clarinetist.
According to a Belgian radio program ("La troisieme oreille", produced by Marc Danval), his name was originally Pierre de la Fontaine.';

$output_string = 'Pete Fountain, is an American, New Orleans based clarinetist.
According to a Belgian radio program ("La troisieme oreille", produced by Marc Danval), his name was originally Pierre de la Fontaine.';

echo '<b>Original string</b>'. "<br>";
echo $sample_string;
echo "<br>";

if (strpos(substr($sample_string, 0, 30), '(') !== false) {

    $newString = preg_replace('/\(.*\)/', '', $sample_string, 1);

    echo "<b>New string</b>" . "<br>";
    echo $newString;
    echo "<br>";
}

echo "<b>Needed output</b>" . "<br>";
echo $output_string;

strpos用于检查字符串的前30个字符内是否有'（'。 preg_replace替换了第一个'（'到第一个'）'字符中的所有字符。

输出：

原始字符串 Pete Fountain（1930年7月3日出生于Pierre Dewey LaFontaine，是一位美国新奥尔良的单簧管演奏家）。根据比利时广播节目（由Marc Danval制作的“La troisieme oreille”），他的名字最初是皮埃尔·德拉方丹。

新字符串 Pete Fountain，是一位美国人，新奥尔良的单簧管演奏家。根据比利时广播节目（由Marc Danval制作的“La troisieme oreille”），他的名字最初是皮埃尔·德拉方丹。

需要的输出 Pete Fountain，是一位美国人，新奥尔良的单簧管演奏家。根据比利时广播节目（由Marc Danval制作的“La troisieme oreille”），他的名字最初是皮埃尔·德拉方丹。

Answer 3

这是你的函数，它也适用于另一个括号内的括号，例如“一个字符串（一些字符串（多一些）一些文本）”。

$ distance是您希望左括号离开头的字符数（在您的情况下为30）

function remove($str, $distance) {
$arr = explode('(', $str);
// if first opening paranthesis is not farther away from distance or if there are no 
// parentheses at all, just return the same string 
if (strlen($arr[0]) >= $distance || count($arr) === 1) {
    return $str;
}

// get the position of first character after the first opening parenthesis 
$currentPos = strlen($arr[0])+1;
$open = '(';
$close = ')';
$openCount = 1;

// loop through each character to find the matching closing parenthesis 
while ($currentPos < strlen($str)) {
    $char = substr($str, $currentPos,1);

    // if we find another opening parenthesis, increase the opening parentheses count
    if ($char == $open) {
        $openCount++;
    }

    // if we find a closing parenthesis, decrease openening parentheses count 
    if ($char == $close) {
        $openCount--;
    }
    // when opening parentheses count is zero, that means we found closing parenthesis 
    // position, so now we can remove the substring between opening and closing 
    // parentheses, including the opening and closing parentheses, and return the 
    // result 
    if ($openCount === 0) {
        $parens = substr($str, strlen($arr[0]), $currentPos - strlen($arr[0])+1);
        return str_replace($parens, '', $str);
    }
    $currentPos++;
}

return $str;
}

Answer 4

试试这个

<?php
$sample_string = 'Pete Fountain (born Pierre Dewey LaFontaine, Jr., July 3, 1930), is an American, New Orleans based clarinetist. 
According to a Belgian radio program ("La troisieme oreille", produced by Marc Danval), his name was originally Pierre de la Fontaine.';
$first_limit='(';
$second_limit=')';
$further=30;
$replace=' ';
echo remove_blablabla_string($sample_string,$first_limit,$second_limit,$further,$replace);

/* FUNCTION */
function remove_blablabla_string($string,$limit1,$limit2,$max_further,$replace_by){
$find=true;
$original_string=$string;
do{
    $string_between=between($string,$limit1,$limit2);
    if($string_between==false)
        $find=false;
    else if(strpos($original_string,$string_between)<=$max_further){
        $string=str_replace($limit1.$string_between.$limit2,$replace_by,$string);
    }else{
        $find=false;
    }
}while($find);
return $string;
}

function between($string,$limit1,$limit2){
$part1=explode($limit1,$string);
if(!isset($part1[1]))
    return false;
$part2=explode($limit2,$part1[1]);
if(!isset($part2[1]))
    return false;
return $part2[0];
}

从位于特定数量的字符后面的字符串中删除带括号的子字符串

实施例

注意：

4 个答案: