我如何得到这样的简单查询
from asg in context.assigmentGen
join agc in context.assignmentContact on asg.contact equals agc.contact
where agc.contact = "123"
我怎么能让它返回true或false?
答案 0 :(得分:1)
(from asg in context.assigmentGen
join agc in context.assignmentContact on asg.contact equals agc.contact
where agc.contact = "123").Any()