Question

我有3张桌子

service - contains（service_id，service_name）
service_req - 包含（service_req_id，requirement）
service_default_req - 包含（service_id，service_req_id，required）此表将服务链接到service_req

这个过程是

首先从services表中获取服务列表;然后
检查这些服务是否具有基于service_default_req表

示例services表

service_id ===== service_name
    1              ticket
    2              tours

示例service_req

service_req_id======requirement
      1           NSO birth cert
      2            OLD passport

将service_default_req

id====service_id=====service_req_id=====required
 1        1                1                0
 2        1                2                0

我使用的功能

function listServices(){
$services= array();
$sql = mysql_query("SELECT * FROM service 
LEFT JOIN service_default_req ON service_default_req.service_id = service.service_id
LEFT JOIN service_req ON service_req.service_req_id = service_default_req.service_req_id    
");
while($temp=mysql_fetch_array($sql)){
    $services[] = array("service_id" => $temp['service_id'], "service_name"=>$temp['service_name'], "requirements"=>array($temp['requirement']), "required"=>$temp['required']);
}
return $services;
}

我得到了什么

Array
(
[0] => Array
    (
        [service_id] => 2
        [service_name] => Passport
        [requirements] => Array
            (
                [0] => NSO Birth Certificate
            )

        [required] => 0
    )

[1] => Array
    (
        [service_id] => 2
        [service_name] => Passport
        [requirements] => Array
            (
                [0] => Old Passport
            )

        [required] => 0
    )

[2] => Array
    (
        [service_id] => 
        [service_name] => Tours
        [requirements] => Array
            (
                [0] => 
            )

        [required] => 
    )
)

我真正需要的是这样的事情。还请注意，为什么第二项服务没有ID？

Array
(
[0] => Array
    (
        [service_id] => 2
        [service_name] => Passport
        [requirements] => Array
            (
                [0] => NSO Birth Certificate
                [1] => Old Passport
            )

        [required] => 0
    )

[1] => Array
    (
        [service_id] => 
        [service_name] => Tours
        [requirements] => Array
            (
                [0] => 
            )

        [required] => 
    )
)

任何帮助都会受到高度赞赏：D

Answer 1

您需要实现一个类似于此处描述的接受答案的数组分组功能：Group a multidimensional array by a particular value?

从3个表格制作数组

1 个答案: