具有分页的Spring-Data FETCH JOIN不起作用

时间:2014-02-04 10:13:14

标签: java spring jpa spring-data spring-data-jpa

我正在尝试使用HQL使用JOIN FETCH获取我的实体以及子实体,如果我想要所有结果,这是正常工作但如果我想要一个页面则不是这样的

我的实体是

@Entity
@Data
public class VisitEntity {

    @Id
    @Audited
    private long id;

    .
    .
    .   

    @OneToMany(cascade = CascadeType.ALL,)
    private List<VisitCommentEntity> comments;
}

因为我有数百万次访问,我需要使用Pageable,我想在单个数据库查询中获取注释,如:

@Query("SELECT v FROM VisitEntity v LEFT JOIN FETCH v.comments WHERE v.venue.id = :venueId and ..." )
public Page<VisitEntity> getVenueVisits(@Param("venueId") long venueId,...,
        Pageable pageable);

该HQL调用抛出以下异常:

Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: query specified join fetching, but the owner of the fetched association was not present in the select list [FromElement{explicit,not a collection join,fetch join,fetch non-lazy properties,classAlias=null,role=com.ro.lib.visit.entity.VisitEntity.comments,tableName=visitdb.visit_comment,tableAlias=comments1_,origin=visitdb.visit visitentit0_,columns={visitentit0_.visit_id ,className=com.ro.lib.visit.entity.VisitCommentEntity}}] [select count(v) FROM com.ro.lib.visit.entity.VisitEntity v LEFT JOIN FETCH v.comments WHERE v.venue.id = :venueId and (v.actualArrival > :date or v.arrival > :date)]
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1374)
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1310)
at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:309)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)

一旦我删除了分页,一切正常

@Query("SELECT v FROM VisitEntity v LEFT JOIN FETCH v.comments WHERE v.venue.id = :venueId and  ..." )
public List<VisitEntity> getVenueVisits(@Param("venueId") long venueId,...);

显然问题是来自Spring-Data的count查询,但是我们如何解决呢?

5 个答案:

答案 0 :(得分:50)

最简单的方法是使用countQuery注释的@Query属性来提供要使用的自定义查询。

@Query(value = "SELECT v FROM VisitEntity v LEFT JOIN FETCH v.comments …",
       countQuery = "select count(v) from VisitEntity v where …")
List<VisitEntity> getVenueVisits(@Param("venueId") long venueId, …);

答案 1 :(得分:4)

或者在最新版本的Spring(支持JPA 2.1规范)中,您可以使用如下的实体图:

@EntityGraph(attributePaths = "roles")
@Query("FROM User user")
Page<User> findAllWithRoles(Pageable pageable);

当然命名实体图也可以。

答案 2 :(得分:2)

您必须为countQuery指定@Query参数,现在您可以使用PageList作为返回值。

@Query(value = "SELECT v FROM VisitEntity v LEFT JOIN FETCH v.comments WHERE v.venue.id = :venueId and ...",
       countQuery = "SELECT count(v) FROM VisitEntity v LEFT JOIN v.comments WHERE v.venue.id = :venueId and ..." )
public Page<VisitEntity> getVenueVisits(@Param("venueId") long venueId,...,
        Pageable pageable);

答案 3 :(得分:0)

尝试countProjection

@Query(value="SELECT v FROM VisitEntity v LEFT JOIN FETCH v.comments WHERE v.venue.id = :venueId and ..." ,
countProjection = "v.id")
public Page<VisitEntity> getVenueVisits(@Param("venueId") long venueId,...,
    Pageable pageable);

答案 4 :(得分:0)

如果您想通过Specification通过连接提取来完全控制查询的构建,则可以检查CriteriaQuery的返回类型并根据查询类型更改连接提取逻辑,如下所示:

public class ContactSpecification implements Specification<Contact> {
    @Override
    public Predicate toPredicate(Root<Contact> root, CriteriaQuery<?> query, CriteriaBuilder cb) {
        if(query.getResultType() == Long.class) {
            root.join(Contact_.company);
        } else {
            root.fetch(Contact_.company);
        }
        return cb.equal(root.get(Contact_.company).get(Company_.name), "Company 123");
    }
}

我无法在文档中找到此信息,但是从SimpleJpaRepository.getCountQuery()方法中,您可以看到查询计数请求的方法:首先为Long返回类型生成计数,然后为期望的类获取数据。

CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<Long> query = builder.createQuery(Long.class);

Root<S> root = applySpecificationToCriteria(spec, domainClass, query);

它是不可靠的,因为它是可以更改的实现细节,但它可以工作。