在Ruby on Rails中，无法使用pg_search查询链接Squeel查询

Question

我想执行以下代码在我的控制器中执行搜索：

experts_controller.erb

@users = User.text_search(params[:query]).has_skill_categories(params[:skills]).has_marketing_assets(params[:marketing_platforms])

当我运行应用程序时，我收到以下错误：

PG::SyntaxError: ERROR:  subquery has too many columns
LINE 1: ...S pg_search_rank FROM "users"  WHERE "users"."id" IN (SELECT...

当我删除使用pg_search的text_search方法时，我得到它按计划工作：

@users = User.has_skill_categories(params[:skills]).has_marketing_assets(params[:marketing_platforms])

你能告诉我为什么我会收到错误以及如何修复错误吗？

这是我的代码。

用户模型 - user.erb

include PgSearch
  pg_search_scope :search, against: [:first_name, :last_name, :company, :description, :job_title, :website, :email, :country, :city, :state],
                  using: {tsearch: {dictionary: 'english'}}

  def self.text_search(query)
    if query.present?
      search(query)
    else
      User.all
    end
  end


  def self.has_marketing_assets(platforms)

    if platforms.present?
      where{users.id.in(User.joins{marketing_assets}.where((['marketing_assets.marketing_platform_id = ?' ] * platforms.count).join(' OR '), *platforms).group{users.id}.having{{marketing_assets => {COUNT(DISTINCT(marketing_assets.marketing_platform_id)) => platforms.count }}})}
    else
      User.all
    end
  end


  def self.has_skill_categories(skills)

    if skills.present?

      where{users.id.in(User.joins{my_skills}.where((['my_skills.skill_id = ?' ] * skills.count).join(' OR '), *skills).group{users.id}.having{{my_skills => {COUNT(DISTINCT(my_skills.skill_id)) => skills.count }}})}
    else
      User.all
    end
  end