Question

我使用struct和pointers（ - ＆gt;）编写了一个小程序。所以我已经声明了一个指向同一结构中另一个对象的对象指针。但是，如果在应用程序上调用delete就会崩溃。

这是错误

Debug Assertion Failed
File:f:\dd\vctools\crt_bld\self_86x\crt\src\dbgdel.cpp
Line 52
Expression:_BLOCK_TYPE_IS_VALID(pHead -> nBlockUse)

这里也是我的代码（p.s当我从程序中删除删除时不会发生此错误）

#include <iostream>
#include <string>
#include <Windows.h>
#include <sstream>
using namespace std;

//declare structure to store info about Billy
struct Son{
    string name;
    string crush;
    int age;
    string hobbies[3];
}Person;

int main(){
    string sAge;
    int i;
    Son* info = new Son;
    info = &Person;
    //user interface
    //Person's name
    cout << "Person's name: ";
    getline(cin, info ->name); //inputs person's name
    //Person's age
    cout << "Person's age: ";
     //inputs person's age
    getline(cin,sAge);
    stringstream ss;
    ss << sAge;
    ss >> info->age;
    info->age = atoi(sAge.c_str());
    //for loop to get hobbies
    for(i = 0; i < 3; i++){
        cout << "Write your hobby[" << i <<"]: ";
        getline(cin,info ->hobbies[i]); //inputs the person hobby three times
    }
    //Person's crush
    cout << "Write your crush name: ";
    getline(cin, info ->crush); //inputs the person's crush *opitional*

    //output statement
    cout << "Name: " << info ->name << endl; //display name
    cout << "Age: " << info ->age << endl; //display age
    for(int j = 0; j < 3; j++){ //display hobbies
    cout << "Hobbies[" << j << "]: " << info ->hobbies[j] << endl;
    }
    cout << "Crush: " << info ->crush << endl; //display crush
    cout << "Deleting memory" << endl;
    delete info;
    info = NULL;
    system("pause");
    return 0;
}

并根据我自己的知识（如果我错了请纠正我）

Son* info = new Son;

此指针（info）具有新语法，应该像这样删除

delete info;

并不确定为什么我会收到此错误

Answer 1

当你这样做时

info = &Person;

使info指向未动态分配的对象。所以你不能在上面调用删除。除此之外，您泄漏了它最初指向的新建Son对象。在任何情况下，似乎都没有理由在代码示例中使用动态分配。

在指针上调用delete时发生C ++崩溃

1 个答案: