Obj-C UserDefaults Char数组的值

Question

我的用户默认值.plist

中有一个值

<key>hex</key>
<data>5448495344414e475448494e474e45454453544f53544159484558</data>

我如何把它放到这样的char []中：

char hex[] = {0x54,0x48,etc..}

我四处搜寻，但没有找到任何例子。我已经尝试了我能想到的一切。

enum {
   NSBinarySearchingFirstEqual = (1 << 8),
   NSBinarySearchingLastEqual = (1 << 9),
   NSBinarySearchingInsertionIndex = (1 << 10),
};
typedef NSUInteger NSBinarySearchingOptions;

NSString *str = @"string";
const char *myChar = "some string";
if (strcmp(myChar,  str.UTF8String))

or

[str isEqualToString:[NSString stringWithUTF8String:myChar]];

CFStringRef myStr = CFSTR("some chars");

bool result = CFStringCompareWithOptions(myStr, ((__bridge CFStringRef)str),CFRangeMake(0,CFStringGetLength(myStr)), kCFCompareCaseInsensitive);

    int someInteger = 42;

    float someFloatingPointNumber = 3.1415;

    double someDoublePrecisionFloatingPointNumber = 6.02214199e23;


    int someInteger = 42;

    someInteger++;            // someInteger == 43



    int anotherInteger = 64;

    anotherInteger--;         // anotherInteger == 63



    anotherInteger *= 2;      // anotherInteger == 126

If you use a scalar type for an Objective-C property, like this:

@interface XYZCalculator : NSObject

@property double currentValue;

@end


@implementation XYZCalculator

- (void)increment {

    self.currentValue++;

}

- (void)decrement {

    self.currentValue--;

}

- (void)multiplyBy:(double)factor {

    self.currentValue *= factor;

}

@end

short myint;
long myint;
unsigned myint;
signed myint;

我问了一个类似的问题，但不是这个问题。