嗨各位大家请帮我这个有关于php jquery功能2框移动选项到另一个框的代码然后选中的框将在提交后插入数据库，我怎么能connect/ insert这个到数据库MySQL的。当我提交它没有错误但没有插入数据库请帮助我。但是jquery功能正在运行。并在phpmyadmin中放置了一些name="food"和type="text"/"varchar"
<html lang="en">
<head>
<title>Catering Service</title>
<meta charset="utf-8">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"> </script>
<script src="js/js.1.js" type="text/javascript"></script>
</head>
<body>
<form action="submit.php" method="post">
<select multiple="multiple" name="food1[]" class="options" id="textarea">
<option name="foodA" value="foodA">foodA</option>
<option name="foodB" value="foodB">foodB</option>
<option name="foodC" value="foodC">foodC</option>
<option name="foodD" value="foodD">foodD</option>
<option name="foodE" value="foodE">foodE</option>
</select>
<button type="button" id="copy" onclick="yourFunction()">Copy</button>
<button type="button" id="remove" onclick="yourFunction()">Remove</button>
<select id="textarea2" multiple class="remove" name="food2[]">
<input type="submit" name="submit" />
</select>
</form>
</html>
<?php
include 'connection.php';
$food2=array ('foodA','foodB','foodC','foodD','foodE');
$food2[0]="foodA";
$food2[1]="foodB";
$food2[2]="foodC";
$food2[3]="foodD";
$food2[4]="foodE";
if(!$_POST['submit']) {
echo "please fill out the form";
header('Location: select.html');
}
else {
$sql = "INSERT INTO remove(foodA, id, foodB, foodC, foodD, foodE) VALUES (?,?,?,?,?);";
$stmt = mysqli_prepare($conn, $sql);
mysqli_stmt_bind_param($stmt,"sssss",$foodA,$id,$foodB,$foodC,$foodD,$foodE);
mysqli_stmt_execute($stmt);
echo "User has been added!";
header('Location: select.html');
}
?>
$(function(){
$("#copy").on("click", function(){
$(".options option:selected").each(function(){
$("#textarea2").append('<option>'+$(this).text()+'</option>');
$('option:selected', "#textarea").remove();
});
});
$("#remove").on("click", function(){
$(".remove option:selected").each(function(){
$("#textarea").append('<option>'+$(this).text()+'</option>');
$('option:selected', "#textarea2").remove();
});
});
});
<?php
$dbhost = "localhost";
$dbuser = "root";
$dbpass = "";
$db = "copy";
$conn = mysqli_connect($dbhost,$dbuser,$dbpass,$db);
?>