Question

如何将一个数组的内容添加到另一个数组中，等于另一个数组。

double[] array1 = new double[4];
double[] array2 = new double[4];
double[] array3 = new double[4];

double input;
double number1;
double number2;

System.out.println("Welcome. Please enter the first number in 1st set: ");

// add 4 numbers into 1st array

System.out.println("Please enter the first number in the 2nd set: ");

// add 4 numbers into 2nd array

for (int i = 0; i < array3.length; i++){
    array3[i] = array1[i] + array2[i];

    System.out.println(" #" + (i+1) + " in the array is " + array3[i]);
}

我不知道为什么底部的代码不起作用。没有出现错误消息，代码中只有0。

我应该这样做：

int number1 = array1[1];
int number2 = array[1];

int finalNumber = number1 + number2;

finalNumber = array3[1];

这似乎不必要地复杂化。

修改的

这是我用来在数组中分配变量的代码。

System.out.println("Welcome. Please enter the first number in 1st set: ");

for (int i = 0; i < array1.length; i++){
    System.out.println(i+1 + ": ");
    input = TextIO.getlnDouble();   // Retrieves input
    input = array1[i];
}

System.out.println("Please enter the first number in the 2nd set: ");

for (int i = 0; i < array2.length; i++){
    System.out.println("Number: ");
    input = TextIO.getlnDouble();   // Retrieves input
    input = array2[i];
}

Answer 1

您错误地分配值。

您应该使用array1[i]=input;代替input = array1[i];。请参阅下文。

for (int i = 0; i < array1.length; i++){
    System.out.println(i+1 + ": ");
    input = TextIO.getlnDouble();   // Retrieves input
    array1[i] = input;
}

System.out.println("Please enter the first number in the 2nd set: ");

for (int i = 0; i < array2.length; i++){
    System.out.println("Number: ");
    input = TextIO.getlnDouble();   // Retrieves input
    array2[i] = input;
}

Answer 2

你的代码很整洁，看起来很好。

您是否打印并检查前两个数组的值？

因为你已经有了

行

double [] array3 = new double [4];

你的for循环没有问题。只需打印前两个数组。

Answer 3

public static void main (String[] args){
        double[] array1 = new double[4];
        double[] array2 = new double[4];
        double[] array3 = new double[4];

        double input;
        double number1;
        double number2;

        System.out.println("Welcome. Please enter the first number in 1st set: ");

        array1[0] = 1;
        array1[1] = 2;
        array1[2] = 3;
        array1[3] = 4;

        for (int i = 0; i < array2.length; i++){
                 System.out.println("Number: ");
                 input = TextIO.getlnDouble();   // Retrieves input
                 //input = array2[i]; <--- change this to
                 array2[i] = input;
             }


        for (int i = 0; i < array3.length; i++){
            array3[i] = array1[i] + array2[i];

            System.out.println(" #" + (i+1) + " in the array is " + array3[i]);
        }
    }

我的输出是

Welcome. Please enter the first number in 1st set: 
Please enter the first number in the 2nd set: 
 #1 in the array is 2.0
 #2 in the array is 4.0
 #3 in the array is 6.0
 #4 in the array is 8.0

也许有帮助=）

Answer 4

你必须改变你的代码

for (int i = 0; i < array2.length; i++){
                 System.out.println("Number: ");
                 input = TextIO.getlnDouble();   // Retrieves input
                 input = array2[i]; <--- change this to
             }

那是正确的

for (int i = 0; i < array2.length; i++){
                     System.out.println("Number: ");
                     input = TextIO.getlnDouble();   // Retrieves input
                     array2[i] = input;
                 }

也是第一个数组

Answer 5

您错误地将值分配给数组。

要将值分配给的变量位于=运算符的左侧。您从分配值的变量位于右侧。

目前，您要将array1[i]中的值指定给input。由于您要将input中的值分配给数组中的某个位置，因此需要更改

input = array1[i];

到

array1[i] = input;

同样使用第二个阵列。

如何将一个数组添加到另一个数组中等于另一个数组

5 个答案: